This is based on calculations too. It contains 18 hydrogen moles.
3H2 + N2 --> 2NH3 is the balanced equation. 13.14g of ammonia is 0.773mol, and that means 1.16mol hydrogen (according to the 2:3 ratio.) 1.16mol of hydrogen = 2.32g of hydrogen.
This value is 0,2 g hydrogen.
how many grams of hydrogen peroxide are needed to produce 5.0 moles of water? how many grams of hydrogen peroxide are needed to produce 5.0 moles of water?
N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3
40 l h2
According balanced equation ,3 mols are needed. So 3mol shoul be mixed
52,4 moles of hydrogen
2,18 g hydrogen are needed.
2,21 g hydrogen are needed.
1,364 g hydrogen are needed.