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The molar mass of potassium chlorate (KClO3) is 122.55 g/mol. This means that 122.55 grams of potassium chlorate yield 3 moles of oxygen gas. To calculate the amount of potassium chlorate that decomposes to yield 30 grams of oxygen, you can set up a simple ratio using the molar masses.
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How many grams of potassium chlorate would be produced by reacting 500 grams of potassium chlorate with oxygen gas?
The reaction between potassium chlorate and oxygen gas generates potassium chloride and oxygen gas. Therefore, the amount of potassium chlorate produced from the reaction is equal to the amount of potassium chlorate that was used, which is 500 grams.
How many grams of potassium chlorate will produce 112.5g of oxygen?
To calculate the amount of potassium chlorate needed to produce 112.5g of oxygen, you first need to determine the molar ratio between potassium chlorate and oxygen. Then, use this ratio to convert the grams of oxygen to grams of potassium chlorate using the molar masses of each compound.
How many grams of oxygen are produced in the decomposition of 6.02g of potassium chlorate?
The decomposition of potassium chlorate produces oxygen gas and potassium chloride. The molar ratio of oxygen to potassium chlorate is 3:2. Therefore, to find the grams of oxygen produced, you would calculate (6.02g * 3 mol O2/2 mol KClO3) * molar mass of O2.
How many grams of potassium chloride are formed by the decomposition of excess potassium chlorate to yield 3.40 L of oxygen?
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
What mass of potassium chlorate would contain 40.0g of oxygen?
To calculate the mass of potassium chlorate containing 40.0g of oxygen, first determine the molar mass of oxygen (16g/mol). Then, use the molecular formula of potassium chlorate (KClO3) to find the oxygen's molar ratio in KClO3 (1:3). Finally, calculate the mass of KClO3 using the molar mass and the molar ratio to find that approximately 186 grams of potassium chlorate contain 40.0g of oxygen.
How many grams of potassium chlorate would be produced by reacting 500 grams of potassium chlorate with oxygen gas?
The reaction between potassium chlorate and oxygen gas generates potassium chloride and oxygen gas. Therefore, the amount of potassium chlorate produced from the reaction is equal to the amount of potassium chlorate that was used, which is 500 grams.
How many grams of potassium chlorate will produce 112.5g of oxygen?
To calculate the amount of potassium chlorate needed to produce 112.5g of oxygen, you first need to determine the molar ratio between potassium chlorate and oxygen. Then, use this ratio to convert the grams of oxygen to grams of potassium chlorate using the molar masses of each compound.
If 25.0 grams of potassium chlorate decomposes, how many grams of potassium chloride will be produced What is the limiting reactant?
I Don't knows Sorry
How many grams of oxygen are produced in the decomposition of 6.02g of potassium chlorate?
The decomposition of potassium chlorate produces oxygen gas and potassium chloride. The molar ratio of oxygen to potassium chlorate is 3:2. Therefore, to find the grams of oxygen produced, you would calculate (6.02g * 3 mol O2/2 mol KClO3) * molar mass of O2.
How many grams of potassium chloride are formed by the decomposition of excess potassium chlorate to yield 3.40 L of oxygen?
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
What mass of potassium chlorate would contain 40.0g of oxygen?
To calculate the mass of potassium chlorate containing 40.0g of oxygen, first determine the molar mass of oxygen (16g/mol). Then, use the molecular formula of potassium chlorate (KClO3) to find the oxygen's molar ratio in KClO3 (1:3). Finally, calculate the mass of KClO3 using the molar mass and the molar ratio to find that approximately 186 grams of potassium chlorate contain 40.0g of oxygen.
If 50 grams of water satured with potassium chlorate 23 Celsius is slowly evaporated to dryness how many grams of the dry salt will be recovered?
If 50 grams of water saturated with potassium chlorate at 23 degrees Celsius is slowly evaporated to dryness, approximately 6.5 grams of the dry salt (potassium chlorate) would be recovered. This is based on the solubility of potassium chlorate in water at that temperature.
How many grams of potassium chlorate are needed to make 250.0ml of a 1.550M potassium chlorate?
To find the grams of potassium chlorate needed, you would first calculate the moles of potassium chlorate using the molarity and volume provided. Then, use the molar mass of potassium chlorate to convert moles to grams. So, the calculation would be: moles = Molarity x Volume (in liters), and then grams = moles x molar mass of potassium chlorate.
How much oxygen gas in grams can be prepared from 86.8 g of potassium chlorate?
To calculate the amount of oxygen gas produced from potassium chlorate, use the balanced chemical equation for the decomposition of potassium chlorate: 2KClO3 -> 2KCl + 3O2. From the equation, every 2 moles of KClO3 produce 3 moles of O2. First, convert the given mass of KClO3 to moles, then use the mole ratio from the balanced equation to find the moles of O2 produced. Finally, convert moles of O2 to grams using its molar mass (32 g/mol).
How many grams of potassium chlorate are needed to make a saturated solution in 200 grams of water at 60 degrees C?
At 60 degrees Celsius, the solubility of potassium chlorate (KClO₃) in water is approximately 7.2 grams per 100 grams of water. To create a saturated solution in 200 grams of water, you would need about 14.4 grams of potassium chlorate (7.2 g/100 g water x 200 g water = 14.4 g KClO₃). Thus, 14.4 grams of potassium chlorate would be required for saturation at this temperature.
How many moles of O2 is made with 3 grams of potassium chlorate?
If the reaction equation is KClO4 -> KCl + 2 O2, as will occur at sufficiently high temperature, 2 moles of O2 will form from each gram formula mass of KClO4. This formula unit mass has the value 138.55; therefore, the number of moles of diatomic oxygen formed will be 2(3/138.55), or about 4 X 10-2 moles. If the integer 3 is considered exact, more significant digits are justified, and the answer can be better approximated as 4.3306 X 10-2
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
Oh, dude, chemistry time! So, when 25 grams of potassium chlorate decompose, you get 74.55% potassium chloride and 25.45% oxygen. So, if you do the math, you'd get around 18.64 grams of potassium chloride. But hey, who's counting, right?
