24 mols of aluminum must have reacted since aluminum oxide is Al2O3
11.1 of moles are required
0.8 mol
1.2 mole
These reagents doesn't react.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
N2 + 3H2 -> 2NH3 3 moles hydrogen gas. You should know that because of the formula of ammonia.
1 mole sulfuric acid for 1 mole calcium chloride
The answer is 699 moles perchloric acid.
These reagents doesn't react.
2,615 moles of aluminium oxide.
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
Ca + 2 H2O ------> Ca(OH)2 + H2 so 2 moles of calcium react with 4 moles of water.
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (Oβ) to form aluminum oxide (AlβOβ) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (AlβOβ). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.
7.54 mol of K
4 moles
4 moles
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
0.8 moles Explanation: from the equation we can see, 2 mole A l is needed to react completely with 3 mole F e O so, 3 moles of F e O needs 2 moles A l so, 1 mole F e O needs 2 3 moles A l so, 1.2 mol F e O needs 2 Γ 1.2 3 moles A l = 0.8 moles A l
This is a mole stoichiometry problem. Start with the balanced equation for the synthesis of aluminum oxide: 4Al + 3O2 --> 2Al2O3. The ratio of aluminum to aluminum oxide in this equation is 4:2, or 2:1, so 5.23 moles Al means half that number for Al2O3, so about 2.62 moles of aluminum oxide will be produced.
1.5 moles of O2 react with 2 moles of Al 2Al + 1.5 O2 = Al2O3.