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How many moles of gas can occupy a 5.0 L flask at 11 degrees Celsius and 5.9 ATM pressure?
Wiki User
∙ 10y ago
Use the Ideal Gas Equation ; PV = nRT
Hence n(moles) = PV/RT
P = 5.9 Atm = 597817.5 Pa
V = 5L = 5.0 x 10^-6 m^3
R = Gas Constant = 8.314 m^3.Pa .K^-1 mol^-1
T = 11oC = 284 K
Substituting
n = 597817.5 Pa X 5.0 x 10^06 m^3 / 8.314 m^3.Pa.K-1 mol^-1 x 284 K
n = 1.29 x 10^-3 moles. = 0.00129 moles
lenpollock
Wiki User
∙ 10y ago1.2653 moles by the ideal gas equation
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