How many moles of NH3 can be produced by the reaction of 2.00 g of N2 with 3.00 g H2 Reaction N2(g) plus 3 H2(g) 2 NH3(g)?

Answer 1

2 mol H2 x 2 mol H2O/2 mol H2 x 18 g H2O/1 mol H2O = 36 g H2O

Answer 2

To determine the limiting reactant, first convert the masses of N2 and H2 to moles. Then divide the amount of each reactant by its stoichiometric coefficient in the balanced equation to find moles of NH3 produced. The limiting reactant is the one that produces the least amount of NH3.

Answer 3

When 6,0 moles of H2 gas react with nitrogen, 4 moles of ammonia are produced.

Answer 4

2,00 moles of ammonia (NH3) have 3 moles of hydrogen.

Answer 5

The result is 786,8 g (theoretically).

Answer 6

0,143 moles of NH3 are produced.

Answer 7

11.3