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What volume of nitrous oxide can be produced from the decomposition of 0.55 moles of ammonium nitrate?
Using the balanced chemical equation for the decomposition of ammonium nitrate, 2NH4NO3 --> 2N2O + O2 + 4H2O, we can see that 2 moles of nitrous oxide (N2O) is produced for every 2 moles of ammonium nitrate (NH4NO3). Therefore, 0.55 moles of NH4NO3 will produce 0.55 moles of N2O. The volume of N2O can then be calculated using the ideal gas law equation (V = nRT/P) and given conditions.
Use the following balanced equation to answer these question n2h4 plus 2h2o2--n2 plus 4h2o how many moles of h2o are produced from 1.5 moles of n2h4?
N2H4 + 2H2O2 -> N2 + 4H2O 1.5 moles N2H4 (4 mole H2O/1 mole N2H4) = 6.0 moles water produced
How many atoms in 4H20?
There are a total of 108 atoms in 4H2O molecules. Each water molecule (H2O) contains 3 atoms (2 hydrogen atoms and 1 oxygen atom). Multiplied by 4 molecules, you get 12 hydrogen atoms and 4 oxygen atoms, totaling 108 atoms.
How many moles of oxygen are necessary to react completely with moles of propane?
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
How many moles of O2 are required to react with 23.5 moles of methanol?
Balanced equation first. 2CH4O + 3O2 -> 2CO2 + 4H2O 23.5 moles methanol (3 moles O2/2 mole CH4O) = 35.3 moles oxygen needed --------------------------------------
How many nitrate ions are in a sample of salt that contains 2 moles of Ca NO3 2 4H2O?
2.4088 x 1024 nitrate ions
What volume of nitrous oxide can be produced from the decomposition of 0.55 moles of ammonium nitrate?
Using the balanced chemical equation for the decomposition of ammonium nitrate, 2NH4NO3 --> 2N2O + O2 + 4H2O, we can see that 2 moles of nitrous oxide (N2O) is produced for every 2 moles of ammonium nitrate (NH4NO3). Therefore, 0.55 moles of NH4NO3 will produce 0.55 moles of N2O. The volume of N2O can then be calculated using the ideal gas law equation (V = nRT/P) and given conditions.
How many moles of manganese are contained in 0 point 1 moles of hydrated manganese II sulphate MnSO4 4H2O which has an RFM of 223?
I must have the same sheet as you as I have the exact same question. Okay, The RFM of Manganese (Mn) is 54.9 The RFM of MnSO4 4H20 is 223 The percentage of Mn in MnSO4 4H2O is 54.9/223 X 100 and that is 24.6 % 0.1 Moles of MnSO4 4H20 is 223/100 X10 = 22.3 24.6 % (percentage of Mn in MnSO4 4H2O) of 22.3 (0.1 Moles of MnSO4 4H2O) is 5.49g Then you do 5.49g/54.9g (RFM of Mn) which is 0.1 Moles of Mn, which is your answer.
Use the following balanced equation to answer these question n2h4 plus 2h2o2--n2 plus 4h2o how many moles of h2o are produced from 1.5 moles of n2h4?
N2H4 + 2H2O2 -> N2 + 4H2O 1.5 moles N2H4 (4 mole H2O/1 mole N2H4) = 6.0 moles water produced
How many atoms in 4H20?
There are a total of 108 atoms in 4H2O molecules. Each water molecule (H2O) contains 3 atoms (2 hydrogen atoms and 1 oxygen atom). Multiplied by 4 molecules, you get 12 hydrogen atoms and 4 oxygen atoms, totaling 108 atoms.
How many moles of oxygen are necessary to react completely with moles of propane?
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
How many moles of HNO3 are required to react with 6 moles of Cu?
The balanced chemical equation for the reaction between copper (Cu) and nitric acid (HNO3) is: 3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O According to the equation, 8 moles of HNO3 are required to react with 3 moles of Cu. Therefore, to react with 6 moles of Cu, you would need 16 moles of HNO3.
How many moles of O2 are required to react with 23.5 moles of methanol?
Balanced equation first. 2CH4O + 3O2 -> 2CO2 + 4H2O 23.5 moles methanol (3 moles O2/2 mole CH4O) = 35.3 moles oxygen needed --------------------------------------
What is the total number of moles of electrons lost by the copper as it completely reacts with 8 moles of nitric acid?
For the reaction between copper and nitric acid, the balanced equation is: 3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O Since each mole of Cu loses 2 moles of electrons, and there are 3 moles of Cu in the balanced equation, the total number of moles of electrons lost by Cu is 6 moles (3 moles of Cu x 2 moles of electrons/mole of Cu = 6 moles of electrons).
How many grams of oxygen are required to complete combustion of 2.75 moles of propane?
C3H8 + 5O2 --> 3CO2 + 4H2O 2.75 mole C3H8 (5 moles O2/1 mole C3H8)(32 grams/1 moleO2) = 440 grams oxygen required =====================
How many moles of Cu must react to produce 4 moles of NO?
3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O is the equation if it is dilute nitric acid. In concentrated nitric acid the equation is different. So 3 moles of copper produce 2 moles of NO. Therefore it requires 6 moles of copper to produce 4 moles of NO.
How many hydrogen atoms are in 4h2o?
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