Copper forms two stable chlorides:
and
as copper is a transition metal its charge can vary however say its charge is 2+ as most transition metals in general are. write a balanced equation: Cu+S-----> CuS an empirical formula is one that contains the simplest whole number ratio of elements, CuS cant get any simpler so it is the empirical formula.
Because copper is a metal and chlorine is a nonmetal, the formula you are looking for is not necessarily empirical. It is more commonly referred to as an ionic formula (because metal-nonmetal bonds are called ionic bonds).
There are two possibilities for your answer:
1. Copper chloride might actually mean to be written as Copper (II) chloride. In that case:
Copper (Cu) is a transition metal and thus can hold various charges when making ionic (metal-nonmetal) bonds. In this case, copper creates bonds with a 2+ charge. Copper will tend to lose 2 e- in the bonding process. This is indicated by the (II) roman numerals after the word copper.
Chlorine (Cl) is a non metal. As a general rule, chlorine will gain 2 electrons in the ionic bonding process, giving chlorine a 2- charge.
Using the criss-cross method of determining the ionic formula, the copper and chloride will combine in a ratio of 2:2 which simplifies to a ratio of 1:1 thus giving you the ionic formula of: CuCl
2. Copper chloride is written correctly. (NO roman numeral!) In that case:
Copper (Cu) is a transition metal and thus can hold various charges when making ionic (metal-nonmetal) bonds. Because there is no roman numeral after copper, we assume there is an understood (I). In this case, copper creates bonds with a 1+ charge. Copper will tend to lose 1 e- in the bonding process.
Chlorine (Cl) is a non metal. As a general rule, chlorine will gain 2 e- in the ionic bonding process, giving chlorine a 2- charge.
Using the criss-cross method of determining the ionic formula, the copper and chloride will combine in a ratio of 1:2, thus giving you the ionic formula of: CuCl2
Elemental copper (which is an element, not a formula) is Cu - from the Latin name of the element, "Cupro".
Cesium sulfate is Cs2SO4
Copper(I) Iodide = CuI
CuSO4 is an empirical formula.
Cu
CH will be the empirical formula and C12H12 will be the molecular formula
C10H22 is the empirical formula of decane.
In this case, the empirical formula and the molecular formula are the same and it is K3PO4.
the empirical formula for fluorine is F. the chemical formula is F2.
The density or some other information must be given that allow you to find the molar mass. Calculate the empirical formula mass. Divide molar mass by empirical formula mass. This answer is multiplied by all subscripts of the empirical formula to get the molecular formula.
CuCl13
It is an empirical formula.
It depends upon the mass of both your copper and oxygen.
An empirical formula refers to the chemical formula that indicates the simplest ratio of atoms in a compound. Two different compounds may have the same empirical formula.
A formula unit is an empirical formula.
A formula unit is an empirical formula.
An empirical formula has no data about the structure of a compound.
The empirical formula of water is H2O.
CH will be the empirical formula and C12H12 will be the molecular formula
X3Y is the empirical formula
C10H22 is the empirical formula of decane.
C5H6O is the empirical formula for Cortisol.