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What is the empirical formula of a compound that contains 4.0 g of hydrogen and 28 g of nitrogen?
Wiki User
∙ 11y ago
Step 1: Convert the mass of each element to moles.
4.0g H x 1mol H/1.00794g H = 4.0 moles H
28g N x 1mol N/14.0067g N = 2.0 moles N
Step 2: Divide each mole value by the smallest number of moles calculated.
H = 4.0 moles/2.0 moles = 2
N = 2.0 moles/2.0 moles = 1
Empirical Formula = NH2
Wiki User
∙ 11y ago
Wiki User
∙ 10y agoEmpirical Formula: NH2
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