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The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.
Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl2
1.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)
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What is the mass of 6.80 moles of magnesium chloride MgCl2 express the value and units?
The molar mass of magnesium chloride MgCl2 is 95.21 g/mol. To find the mass of 6.80 moles, you would multiply the number of moles by the molar mass: 6.80 moles * 95.21 g/mol = 647.868 g. Therefore, the mass of 6.80 moles of MgCl2 is 647.868 grams.
How many moles of MgCl2 are there in 317 g of the compound?
To find the number of moles of MgCl2 in 317 g of the compound, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to get the number of moles: 317 g / 95.21 g/mol = 3.33 moles of MgCl2.
What is the mass of 9.40 moles of magnesium chloride MgCl2?
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
105 g of MgCl2 contains how much mol MgCl2?
First, we calculate the molar mass of MgCl2, which is 95.21 g/mol. Then, we divide the given mass by the molar mass to determine the number of moles of MgCl2. So, 105 g of MgCl2 contains approximately 1.10 moles of MgCl2.
How many moles are there in 0.684g MgCl2?
To find the number of moles in 0.684g of MgCl2, you need to divide the mass by the molar mass of MgCl2. The molar mass of MgCl2 is 95.211 g/mol (24.305 g/mol for Mg and 35.453 g/mol for Cl). Dividing 0.684g by 95.211 g/mol gives approximately 0.0072 moles of MgCl2.
What is the mass of 6.80 moles of magnesium chloride MgCl2 express the value and units?
The molar mass of magnesium chloride MgCl2 is 95.21 g/mol. To find the mass of 6.80 moles, you would multiply the number of moles by the molar mass: 6.80 moles * 95.21 g/mol = 647.868 g. Therefore, the mass of 6.80 moles of MgCl2 is 647.868 grams.
How many moles of MgCl2 are there in 317 g of the compound?
To find the number of moles of MgCl2 in 317 g of the compound, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to get the number of moles: 317 g / 95.21 g/mol = 3.33 moles of MgCl2.
What is the mass of 9.40 moles of magnesium chloride MgCl2?
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
105 g of MgCl2 contains how much mol MgCl2?
First, we calculate the molar mass of MgCl2, which is 95.21 g/mol. Then, we divide the given mass by the molar mass to determine the number of moles of MgCl2. So, 105 g of MgCl2 contains approximately 1.10 moles of MgCl2.
How many moles are there in 0.684g MgCl2?
To find the number of moles in 0.684g of MgCl2, you need to divide the mass by the molar mass of MgCl2. The molar mass of MgCl2 is 95.211 g/mol (24.305 g/mol for Mg and 35.453 g/mol for Cl). Dividing 0.684g by 95.211 g/mol gives approximately 0.0072 moles of MgCl2.
How many grams of MgCl2 are needed to make 700.mL of a 1.4 M solution?
To determine the grams of MgCl2 needed for a 1.4 M solution in 700 mL, we first calculate the moles of MgCl2 required using the formula Molarity (M) = moles/volume(L). Moles = Molarity x Volume(L). Moles = 1.4 mol/L x 0.7 L = 0.98 moles. Next, we calculate the molar mass of MgCl2 (95.21 g/mol) and then multiply the moles by the molar mass to find the grams needed: 0.98 moles x 95.21 g/mol = 93.3 grams of MgCl2.
How many moles are contained in 444 grams of magnesium chloride?
To find the number of moles in 444 grams of magnesium chloride, you first need to calculate the molar mass of magnesium chloride. The molar mass of MgCl2 is about 95.21 g/mol. Next, calculate the number of moles by dividing the given mass by the molar mass: 444 g / 95.21 g/mol ≈ 4.66 moles of magnesium chloride.
What is the mass of 6.10 moles of magnesium chloride?
The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
What is the molarity of 80g magnesium chloride dissolved in 250ml of water?
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
What is the molarity of a solution that is made by dissolving 75.0 grams of MgCl2 in 500.0 milliliters of solution?
Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution --------------------------------
124 g of MgCl2 contains __.mol MgCl2?
Mgcl2 contain molar mass=24.31+ 2(35.45)= 95.21 g/mol 124g of Mgcl2 contains moles= 95.21* 124=11806.04moles
How many formula units make up 32.0 g of magnesium chloride (MgCl2)?
To find the number of formula units in 32.0 g of magnesium chloride (MgCl2), you first need to calculate the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 g/mol. Next, divide the given mass by the molar mass to get the number of moles, and then use Avogadro's number to convert moles to formula units. So, 32.0 g / 95.21 g/mol ≈ 0.336 moles of MgCl2, and then using Avogadro's number, this corresponds to approximately 2.02 x 10^23 formula units of MgCl2.
