Q: What is the mass of 5.55 1022 formula units of calcium chloride CaCl2?

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The chemical formula for the compound calcium chloride is CaCl2. The atomic mass of CaCl2 is 40.1 + 2(35.5) = 111.1Amount of CaCl2 = mass of pure sample/molar mass = 0.2/111.1 = 0.00180mol There are 0.00180 moles of CaCl2 in a 0.2 gram pure sample.

The answer is 3,33 moles.

formula units

0,355 formula units make up 33,8 g of magnesium chloride (MgCl2).

The gram formula unit mass of magnesium chloride is 95.21. Therefore, 21.2g of magnesium chloride make up 21.2/95.21 or 0.223 formula units, to the justified number of significant digits.

Related questions

1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2

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The chemical formula for the compound calcium chloride is CaCl2. The atomic mass of CaCl2 is 40.1 + 2(35.5) = 111.1Amount of CaCl2 = mass of pure sample/molar mass = 0.2/111.1 = 0.00180mol There are 0.00180 moles of CaCl2 in a 0.2 gram pure sample.

The answer is 3,33 moles.

A same number.

A mole is 6.022 × 1023 so 2.41 × 1024 molecules CaCl2 ÷ 6.022 × 1023 = 4.00 moles CaCl2.

formula units

0,355 formula units make up 33,8 g of magnesium chloride (MgCl2).

The answer is 2,09 moles.