Molarity = moles of solute/Liters of solution
Get moles NaCl.
58.44 grams NaCl (1 mole NaCl/58.44 grams)
= 1 mole NaCl
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Molarity = 1 mole NaCl/1 liter
= 1 M NaCl
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Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
Mole = Mass/RMM Ar for Na=23 & Ar for Cl = 35.5 Therefore 1mole = Mass / (35.5+23) 1 mole of NaCl is 58.5g Mole = Mass/RMM Ar for Na=23 & Ar for Cl = 35.5 Therefore 1mole = Mass / (35.5+23) 1 mole of NaCl is 58.5g But that can be misleading. NaCl does not form into molecules (and salts in general do not). If you dissolve 58.5g of NaCl into water, it will dissociate into ions, and there will be 2 moles of particles in solution: 1 mole of Na+ ions, and 1 mole of Cl- ions. Knowing that will be important for calculating various things, such as how many degrees the freezing point will be depressed, when you dissolve so much salt in so much water.
In the same volume of water, one mole of MgCl2 will give rise to a greater boiling point elevation. This is explained by the fact that boiling point elevation is a colligative property, that is, the relative amounts of the constituents are important and not their identity. We can determine by inspection that, upon dissociation, more ions will be produced by MgCl2 than NaCl since there are more atoms in the MgCl2 molecule. So, for one mole of MgCl2, we will produce one mole of magnesium and two of chlorine (three total). For one mole of NaCl, we produce one mole each of potassium and chlorine. By employing the principle stated above, we can come to the correct conclusion.
Molar concentration is the number of moles of a substance per litre. One litre of pure water is 1kg, or 1,000 grams. The molecular mass of water is approximately 18 grams per mole. Therefore, there are 1,000/18 = 55.56 mole of water in a litre of water, giving a concentration of 55.56 M.
1 mole NaCl = 6.022 x 1023 formula units NaCl 2.9 x 1021 formula units NaCl x 1mol NaCl/6.022 x 1023 formula units NaCl = 0.0048 mole NaCl
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
You need to know the molar mass of NaCl. Then 10g/molar mass = moles.
1 mole NaCl = 58.44g 0.1601mol NaCl x 58.44g NaCl/mol NaCl = 9.35g NaCl
.15
145 grams NaCl (1 mole NaCl/58.44 grams)(1 mole Na +/1 mole NaCl)(6.022 X 1023/1 mole Na +) = 1.49 X 1024 ions of sodium =====================
The number of ions in a 6,58 mole sample of NaCl is 79,25137367812.10e23.
In the same volume of water, one mole of MgCl2 will give rise to a greater boiling point elevation. This is explained by the fact that boiling point elevation is a colligative property, that is, the relative amounts of the constituents are important and not their identity. We can determine by inspection that, upon dissociation, more ions will be produced by MgCl2 than NaCl since there are more atoms in the MgCl2 molecule. So, for one mole of MgCl2, we will produce one mole of magnesium and two of chlorine (three total). For one mole of NaCl, we produce one mole each of potassium and chlorine. By employing the principle stated above, we can come to the correct conclusion.
Mole = Mass/RMM Ar for Na=23 & Ar for Cl = 35.5 Therefore 1mole = Mass / (35.5+23) 1 mole of NaCl is 58.5g Mole = Mass/RMM Ar for Na=23 & Ar for Cl = 35.5 Therefore 1mole = Mass / (35.5+23) 1 mole of NaCl is 58.5g But that can be misleading. NaCl does not form into molecules (and salts in general do not). If you dissolve 58.5g of NaCl into water, it will dissociate into ions, and there will be 2 moles of particles in solution: 1 mole of Na+ ions, and 1 mole of Cl- ions. Knowing that will be important for calculating various things, such as how many degrees the freezing point will be depressed, when you dissolve so much salt in so much water.
1 mole
Molar concentration is the number of moles of a substance per litre. One litre of pure water is 1kg, or 1,000 grams. The molecular mass of water is approximately 18 grams per mole. Therefore, there are 1,000/18 = 55.56 mole of water in a litre of water, giving a concentration of 55.56 M.
1 mole NaCl = 58.44g NaCl0.48mol NaCl x 58.44g NaCl/1mol NaCl = 28g NaCl
1.5g NaCl x (1 mole / 58.5 g NaCl) x (1000 ml / 0.42 mole) = 61.05 ml