Group 1 and 2 elements have 1 and 2 valence electrons respectively. Removal of these electrons will result in stable noble gas electronic configuration. Group 17 and 16 elements have 7 and 6 valence electrons respectively. Addition of 1 or 2 electrons to group 17 and 16 respectively will give them stable noble gas configuration.
Hence these two groups are highly reactive and their elements will combine to form large number of compounds.
The ionic compound formed when cesium reacts with oxygen is cesium oxide (Cs2O). In this compound, cesium, a group 1 metal, donates its outer electron to oxygen, a group 16 nonmetal, to form a stable ionic bond.
Chlorine (Cl) will bond with potassium (K) to form an ionic compound, potassium chloride (KCl). In this compound, potassium will donate its outer electron to chlorine, resulting in the formation of a positive potassium ion and a negative chloride ion.
The formula for the ionic compound formed between strontium (Sr) and tellurium (Te) is SrTe. Strontium is a group 2 element, providing a 2+ cation, while tellurium is a group 16 element, providing a 2- anion. The compound is neutral and balanced with a 1:1 ratio of Sr to Te.
The formula for the ionic compound formed between strontium (Sr) and sulfur (S) is SrS. Strontium is a group 2 element with a 2+ charge, while sulfur is a group 16 element with a 2- charge. Therefore, they combine in a 1:1 ratio to form a neutral compound.
Oxygen is the most active nonmetallic element in group 16, also known as the oxygen group or chalcogens. It readily reacts with many elements to form oxides.
The ionic compound formed when cesium reacts with oxygen is cesium oxide (Cs2O). In this compound, cesium, a group 1 metal, donates its outer electron to oxygen, a group 16 nonmetal, to form a stable ionic bond.
Chlorine (Cl) will bond with potassium (K) to form an ionic compound, potassium chloride (KCl). In this compound, potassium will donate its outer electron to chlorine, resulting in the formation of a positive potassium ion and a negative chloride ion.
The formula for the ionic compound formed between strontium (Sr) and tellurium (Te) is SrTe. Strontium is a group 2 element, providing a 2+ cation, while tellurium is a group 16 element, providing a 2- anion. The compound is neutral and balanced with a 1:1 ratio of Sr to Te.
The formula for the ionic compound formed between strontium (Sr) and sulfur (S) is SrS. Strontium is a group 2 element with a 2+ charge, while sulfur is a group 16 element with a 2- charge. Therefore, they combine in a 1:1 ratio to form a neutral compound.
Oxygen is the most active nonmetallic element in group 16, also known as the oxygen group or chalcogens. It readily reacts with many elements to form oxides.
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Yes, sodium oxide (Na2O) forms an ionic compound. Sodium (Na) gives up an electron to oxygen (O) to form Na+ and O2- ions which then combine in a 1:1 ratio to form Na2O. The formula of the ionic compound is not commonly represented as x2y, but rather as Na2O.
Yes, in the reaction between barium and oxygen to form an ionic compound, barium atoms will lose 2 electrons to form a Barium cation with a 2+ charge. Oxygen will gain those 2 electrons to form an oxide anion with a 2- charge.
Group 1 elements can form 1 bond, Group 14 can form 4 bonds, Group 16 can form 2 bonds, and Group 17 can form 1 bond.
Since CD has a 3:8 ratio of C to D, we can infer that CD2 would have a 3:16 ratio of C to D. To form CD2, you would need 16 grams of element D for every 3 grams of element C, resulting in a total of 19 grams for compound CD2.
Group 16 or the chalcogens.
Group 1 and 2 elements have 1 and 2 valence electrons respectively. Removal of these electrons will result in stable noble gas electronic configuration. Group 17 and 16 elements have 7 and 6 valence electrons respectively. Addition of 1 or 2 electrons to group 17 and 16 respectively will give them stable noble gas configuration. Hence these two groups are highly reactive and their elements will combine to form large number of compounds.