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Q: How many grams of calcium nitrate are needed to make a 500 ml volume of a .5 molar solution?

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Volume mL= 32.76 mL x 0.0215 M/ 0.03455 = 20.386 mL calcium hydroxide solution.

The answer is 252,05 mL.

Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.

By definition, a 0.61M sodium nitrate solution contains 0.61 moles of sodium nitrate per liter, which is equivalent to 0.61 mmol/ml. Therefore, the volume of this solution required to contain 400mmol is 400/0.61 or 6.6 X 102 ml, to the justified number of significant digits.

The volume is 79,85 mL.

Look up molecular mass of lead nitrate in the periodic table. Formula of lead nitrate is Pb(NO3)2 Molecular mass is 331.2 gm/mole A one molar solution has 1 mole per liter of solution. 13.6 grams/331.2 gm/mole = 0.041 moles 0.041 moles/0.15 molar = .274 liters This is not exactly correct, because when you add a solute to a solvent, the volume of the solution may be more or less than the original volume of solvent, depending upon the interaction of the solvent and the solute. Actually, the final volume of solution should be 0.274 liters. The most accurate way is to dissolve the solute is slightly less than the calculated amount of solvent needed, and then adjust the volume to the final amount after the solute is completely dissolved.

You cannot make a solution of AgCl, it is an insoluble salt

how many moles are there in 56.0 grams of silver nitrate?

25 mL

No. you will know the volume of the unknown mass after you calculate the mass of ca0

The answer is 770,9 mL solution.

It depends on the Molarity of the solution. if the (mols x molar mass)/volume> 1, its more dense.

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