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How much heat would it take to raise 10 pounds of water from 40 degrees to 41 degrees f?
Wiki User
∙ 11y ago
the answer is 200 Btu.
the formula is
weight x specific heat x temperature difference
so we have
10 pounds x 1.00 x 20
10 for 10 pounds of water
the specific heat of water is 1.00
and the temperature difference would be 70-50= 20
Wiki User
∙ 13y ago
Wiki User
∙ 11y agoConversion first.
10 pounds water = 4540 grams
40o F = 4.4o C
41o F = 5o C
q = mass * specific heat * change in temperature
q = (4540 g)(4.180 J/gC)(41o C - 40o C)
= 1.9 X 104 Joules of heat
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Wiki User
∙ 14y agoType your answer here... What is the amount of heat required to raise the temperature of 10 gallons of water from 64 degrees to 74 degrees?
Wiki User
∙ 13y agoAnything over the present temperature of the water will do it. less just means a longer duration is needed if it's low heat.
Wiki User
∙ 12y ago376 J. Energy = 4,18 KJ/(kg*K) * 0,0045 kg * 20 K = 376,2 J
Wiki User
∙ 13y ago10.6 kilojoules (approx)
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