Do you want that for Monopotassium phosphate, dipotassium phosphate, or tripotassium phosphate? --------------------------------- To clarify for the previous answerer, ionic compounds inherently don't use the mono-, di-, or tri- system used for molecular compounds. Instead, when a cation and an anion is supplied, the ionic compound assumes the number of cations and anions that will generate a neutral ionic compound. In this case, since K is 1+ and PO4 is 3-, the compound potassium phosphate always refers to K3PO4. Therefore: 3AgNO3 + K3PO4 -> 3KNO3 + Ag3PO4
The Balanced equation for Silver Nitrate and Potassium Chloride is:
AgNO3 + kCl --> AgCl+ KNO3 (silver chloride and potassium nitrate)
This equation is balanced because the number of atoms of the elements on both sides are the same.
Balanced:
AgNO3 + KI ----> KNO3 + AgI
Silver Potassium Cyanide = AgK(CN)2........ Potassium Carbonate = K2CO3........ Potassium Hydroxide = KOH........ Potassium Cyanide = KCN
Silver nitrate + potassium iodide -> silver iodide + potassium nitrate
AgNO3 + KI -----> AgI + KNO3
Silver thiocynate is formed, AgNO3 + KSCN ------> AgSCN + KNO3
2AgNO3 + K2CrO4 -> Ag2CrO4 + 2KNO3
AgNO3 + KBr -----> AgBr + KNO3
AgNO3 + KBr
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
Ag(NO3)(aq) + KI(aq) ---> K(NO3)(aq) + AgI(s)
Pb2+ + I- --> PbI2(s)potassium and acetate ions are left out of the equation, because they don't react (stay unchanged in solution)
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
pb(No3)2 +2KI -------> 2KNo3+pbI2
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
The products are Mercury(II) iodide and Potassium nitrate
Potassium nitrate and a precipitate of Silver iodide are formed
It produces Potassium nitrate and Lead iodide
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
A reaction doesn't occur.
A precipitate of Lead iodide and Potassium nitrate are formed
potassium