Q: To 225 mL of a 0.80M solution of KI a student adds enough water to make 1.0 L of a more dilute KI solution What is the molarity of the new solution?

Write your answer...

Submit

Still have questions?

Related questions

A solution that only contains a small amount of solute, is a dilute or very dilute solution.

To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.

The molarity is calculated by dividing the moles of solute by the liters of solution. In this case, the molarity would be 3.09 moles / 1.50 L = 2.06 M.

To prepare a 0.1N NaOH solution, dissolve 4g of sodium hydroxide (NaOH) pellets in enough water to make 1 liter of solution. Use a volumetric flask to accurately measure the final volume. Remember to handle NaOH with caution as it is a caustic substance.

To determine the molarity, first calculate the number of moles of C6H12O6 using its molar mass. Then, divide the number of moles by the total volume in liters to get the molarity. In this case, the molarity would be around 0.48 M.

To find the molarity, start by converting grams of sulfuric acid to moles. the molar mass of sulfuric acid (H2SO4) is 98.08 g/mol. Divide the moles by the volume in liters (500.0 mL = 0.5 L) to get the molarity. Molarity = moles/volume (L).

0.570 M (note the capital M, this is molarity.)

To find the molarity, first calculate the number of moles of potassium nitrate using its molar mass (101.1 g/mol). This comes out to 0.2 moles. Then, divide the moles by the volume of the solution in liters (0.250 L) to get the molarity, which is 0.8 M.

To find the concentration of the H2C2O4 solution, you first need to determine the molarity of the solution. Calculate the number of moles of H2C2O4 x 2H2O using its molar mass, then divide that by the volume of the solution in liters to find the molarity. Finally, remember to account for the stoichiometry of the compound in the calculations.

Calculating the freezing point depression of a solvent requires three pieces of information: 1) the molal freezing point depression of that solvent; 2) the molality of the solution; 3) the number of distinct entities produced in solution per molecular formula unit of solute. Hopefully you meant molality instead of molarity (if the solvent is water and it's a dilute solution, assuming that molality = molarity isn't a bad approximation). I suspect you've been told what 1 and 3 are (or been given enough information to figure them out) but simply didn't mention it; otherwise you're pretty much boned.

The molar mass of HCl is 36.46 g/mol. So, 1.56 grams of HCl is equivalent to 0.0428 moles. Since the volume of the solution is 26.8 mL (0.0268 L), the molarity is calculated as 0.0428 moles / 0.0268 L = 1.60 M.

To calculate the molarity of the solution, first convert the volume to liters (150 mL = 0.150 L). Then, divide the moles of solute (0.20 mol NaOH) by the volume of solution in liters to get the molarity. Molarity = 0.20 mol / 0.150 L = 1.33 M.