Unless I've completely forgotten my chemistry, mole fraction is the fraction of moles of a particular solute of the entire number of moles in the solution. So for this question: formula weight of ethanol = 46.07 g/mol formula weight of water = 18.015 g/mol moles of ethanol = 47.5g / 46.07 g/mol = 1.0310 mol moles of water = 850g / 18.015 g/mol = 47.182 mol total number of moles in the solution = 1.0310 + 47.182 = 48.213 mol therefore, the mole fraction of ethanol is 1.0310 mol / 48.213 mol = 0.0214 hope this helps.
First, calculate the volume percentages of ethanol and water in the solution. Since we know the density of both solvents, convert the percentages to mass (using density and volume). Then calculate the mole fraction of ethanol by dividing the moles of ethanol by the total moles of all components in the solution. Finally, calculate molality using the moles of solute (ethanol) and the mass of the solvent (water).
To calculate the mole fraction of water in the solution, we first need to determine the moles of water and ethanol present. Given that the solution is 57% water by mass, we can assume the remaining 43% is ethanol. From there, we can convert the mass percentages to moles using the molar masses of water and ethanol, and finally, calculate the mole fraction of water by dividing the moles of water by the total moles of the solution.
To find the mole fraction of ethanol, you first calculate the total moles of the solution, which is 3.00 + 5.00 = 8.00 moles. Then, you divide the moles of ethanol by the total moles of the solution: 3.00 moles / 8.00 moles = 0.375. So, the mole fraction of ethanol in the solution is 0.375.
It depends a bit on what information you are given. However, the principle is the same in all cases, although how you do the specific calculation may vary a bit.As an example, let's say we have a mixture of 5.00 grams of water and 10.0 grams of ethanol (C2H5OH). What is the mole fraction of the two components?The first thing we must do is convert the number of grams of each substance into moles. To do that, see the Related Question below:How do you convert from grams to moles and also from moles to grams?For water, we have:5.00 grams ÷ 18.015 grams/mole = 0.2775 moles H2OFor ethanol, we have:10.0 grams ÷ 46.068 grams/mole = 0.2171 moles C2H5OHNow we can find the mole ratio, which is defined as follows:Moles ratio of compound X = number of moles of X ÷ total number of moles in mixtureSo the mole ratio of water is: 0.2775 ÷ (0.2775 + 0.2171) = 0.561 or 56.1%and the mole ratio of ethanol is: 0.2171 ÷ ((0.2775 + 0.2171) = 0.439 or 43.9%Check your answer! The total mole ratio for all components MUST add up to 1.00:0.561 + 0.439 = 1.00 Yes!Note that the weight ratio was 1-to-2 (twice as much ethanol as water by weight), but the mole ratio was completely different.
The answer is 31,05 g ethanol.
The mixture of ethanol in water is a homogeneous mixture because ethanol and water molecules mix evenly and form a single phase without easily visible boundaries between the two substances.
Almost no salt will dissolve in pure ethanol. If salt is added to a solution of ethanol and water, which are miscible, it may form a homogenous solution without being stirred.
The total volume of the solution is 10ml + 40ml = 50ml. The percentage concentration of ethanol in the solution is (10ml / 50ml) * 100% = 20%.
After 50 grams of water evaporate, you will be left with 50 grams of water in which the 3.0 grams of salt is dissolved. So, your solution will now contain 3.0 grams of salt dissolved in 50 grams of water.
No this is not an ideal solution, because water and alcohol (ethanol) molecules interact rather complex resulting in eg. an azeotropic boiling point at 96% mixture
The polarity difference between ethanol and water affects their interactions in a solution because water is a polar molecule with positive and negative charges, while ethanol is also polar but less so. This difference in polarity allows ethanol and water to mix well together, forming a homogeneous solution. The positive and negative charges in water attract the ethanol molecules, leading to strong interactions between the two substances.
Divide the mass of the ethanol by the sum of the mass of the ethanol + that of the water and multiply by 100. Mass ethanol/(Mass ethanol + mass H2O) (x100)