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You don't need the voltage to calculate that. Just use the product-over-sum formula (for two resistors):

R = (R1 x R2)/(R1 + R2)

Where R is the equivalent resistance, and R1 and R2 are the individual resistances.

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7y ago
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VS Waterproofing

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7mo ago

When resistors are connected in parallel, you can calculate the equivalent resistance using the following formula:

1 / Req = 1 / R1 + 1 / R2 + 1 / R3

In your case, you have three 15-ohm resistors connected in parallel, so R1 = R2 = R3 = 15 ohms.

1 / Req = 1 / 15 ohms + 1 / 15 ohms + 1 / 15 ohms

Now, calculate the sum of the reciprocals:

1 / Req = (1/15) + (1/15) + (1/15) = 3/15

Now, invert both sides of the equation to find Req:

Req = 15 / 3

Req = 5 ohms

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10y ago

The equivalent resistance of three 15-ohm resistors in parallel is 5 ohms.

It doesn't matter what the voltage of the battery is, or even whether or not

they're even connected to a battery. They can be wrapped in cloth and stuffed

in a box in the back of a drawer in a dark room somewhere. Their equivalent

resistance is still 5 ohms.

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14y ago

5 ohms...

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9y ago

2 amps

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Kudzai valentine Mab...

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1y ago

15

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Q: Three 15 ohm resistors are connected in parallel to a 30 volt battery What is the equivalent resistance through the circuit?
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What is the equivalent resistance when resistors are in a cube?

The equivalent resistance, from corner to corner, of 12 resistors connected in a cube is 5/6 that of a single resistor.Proof:Start from one corner and flow current through to the opposite corner. You have three resistors. Each of those three resistors is connected to two resistors, in a crisscross pattern. Those six resistors are then connected to three resistors which are connected to the other corner. By symmetry, the voltages at the upper junctions are the same, and then same can be said for the lower junction. You can then simplify the circuit by shorting out the upper junctions and (separately) the lower junctions. This means the circuit is equivalent to three resistors in parallel, in series with six resistors in parallel, in series with three resistors in parallel. This is 1/3 R plus 1/6 R plus 1/3 R, or 5/6 R.


If a 1 ohm resistor is parallel with a 100 ohm resister what's the total resistance?

If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.


What is the resistance between any two of the corners if Three 3 ohm resistors are connected such that it make triangle.?

2 ohms. It is like connecting two 3 ohm resistors in series and then these two series resistors are connected in parallel with third 3 ohm resistor in parallel


What is the equivalent resistance of a pair of 8 ohm resistors in series circuit?

Two eight-ohm resistors in series would have a total resistance of 16 ohms. Two eight-ohm resistors in parallel would have a total resistance of four ohms.


Is it possible to connect a group of resistors of value R in such a way that the equivalent resistance is less than R?

Yes. When resistors are connected in "parallel" (all the left ends connected together and all the right ends connected together) the effective resistance is always less then the smallest resistor in the group. For example If you connected a 2 ohm in parallel with a 4 ohm the effective resistance is 1.33 ohm. To your question; if you connect N equal resistors R in parallel the effective resistance would be R/N . The formula for calculating effective resistance R of a group R1, R2, R3, ... in parallel is: 1/R = 1/R1 + 1/R2 + 1/R3 + .... Note; write the right side as a single fraction by getting a common denomenator then invert to get R.

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Which is the total resistance of a circuit that contains twenty 100 ohms resistors connected in parallel?

When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.


When 2 resistors are connected in parallel r1r2 are?

Two resistors connected in parallel are 1/2 the sum of their resistance. The resistance of two resistors connected in series is the sum of their resistance. For example: The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in parallel is 100+200 divided by 2 = 150 ohms. The total resistance of a 100 ohm resistor connected to a 200 ohm resistor in series 100+200= 300 ohms.


To connect a pair of resistors so that their equivalent resistance is greater than the resistance of either one should you connect them in series or in parallel?

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How do you calculate the equivalent resistance connected together in parallel?

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How do you connect several resistances if you want to decrease in total resistance without reducing the number of resistors?

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How can you connect resistors to produce an equivalent resistance which is the same as the resistance of each individual resistor?

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Do 5 1 ohm resistors equal 1 5 ohm resistor?

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How to find Equivalent resistance when you have both parallel and series resistors?

To find equivalent resistance when you have both parallel and series resistors, start simple and expand... Find the smallest part of the circuit, such as a pair of resistors in series or a pair of resistors in parallel, and compute the equivalent single resistor value. Repeat that process, effectively covering more and more of the circuit, until you arrive at a single resistance that is equivalent to the circuit. For resistors in series: RTOTAL = R1 + R2 For resistors in parallel: RTOTAL = R1R2/(R1+R2)


What is the equivalent resistance when resistors are in a cube?

The equivalent resistance, from corner to corner, of 12 resistors connected in a cube is 5/6 that of a single resistor.Proof:Start from one corner and flow current through to the opposite corner. You have three resistors. Each of those three resistors is connected to two resistors, in a crisscross pattern. Those six resistors are then connected to three resistors which are connected to the other corner. By symmetry, the voltages at the upper junctions are the same, and then same can be said for the lower junction. You can then simplify the circuit by shorting out the upper junctions and (separately) the lower junctions. This means the circuit is equivalent to three resistors in parallel, in series with six resistors in parallel, in series with three resistors in parallel. This is 1/3 R plus 1/6 R plus 1/3 R, or 5/6 R.


Characteristics of resistor in series and parallel connection?

Resistors in series add resistance to an electrical circuit. For instance two 1 ohm resistors in series will have 2 ohms of resistance. Resistors in parallel divide the resistance between them. Thus two 2 ohm resistors in parallel will have 1 ohms total resistance. resistors of different sizes work the same way. a 4 ohm and 2 ohm resistor in series have 6 ohms resistance. While in parallel they will have .75 ohm resistance. resistance formulas: series: Req = r1+r2+r3....+rx parallel: Req = 1/r1 + 1/r2 + 1/r3 ..... +1/rx


What is a resistance network?

A resistance 'network' consists of a number of resistors connected together in series, or in parallel, or in series-parallel, or as a complex circuit. A 'complex' circuit is one that is not series, parallel, or series-parallel.