In a DC circuit, the power dissipated by a resistance is (voltage across it)2 divided by 'R'.
P = E2/R = (14.1)2 / 142 = 198.81/142 = 1.4 watts(rounded)
7.0w/4 = 1.75w
No. Load resistance is the value of the element actually doing the work of the circuit it is connected to. A speaker connected to an amplifier is the load.
Parallel resistance refers to 2 or more resistors where the input sides are connected together and the output sides are connected together. The formula to calculate it is the inverse of the total resistance of the circuit is equal to the sum of the inverses of the individual resistances. 1/R (total) = 1/R (1) + 1/R (2) + 1/R (3) + …
You need to calculate the equivalent resistance. For instance, if the three resistors are connected in series, simply add all the resistance values up. Then, you calculate the current (in amperes) using Ohm's Law (V=IR); that is, you need to divide the voltage by the resistance.
That's like having a series combination of 4 + 4 ohms, in parallel with another resistance of 4 ohms. Calculate the series resistance, then use the parallel formula to combine it with the third resistance.
If three equal resistors are connected in parallel, the equivalent resistance will be one-third of the resistance in series. This lower resistance will result in a higher current flowing through the resistors when connected in parallel compared to when they are in series. Therefore, the power dissipated by the resistors in parallel will be greater than 10W.
7.0w/4 = 1.75w
To find the net resistance of the circuit connected to the battery in the figure, you need to calculate the total resistance by adding up the individual resistances in the circuit.
about 27ohms
Resistance is connected in parallel with voltmeter or say, voltmeter is connected in parallel with resistance.
This question can be answered using voltage dividers. Assume the power supply consists of a voltage source and a resistor. With no load, all of the voltage source's voltage is dissipated by the internal resistor of 15V. When there is a load, there are two resistors in series. To calculate the internal resistance:1. I=V/R. You know the 600ohm resistor dissipated 13.7V. So that would mean a current of 13.7/600=22.8mA2. If the 600ohm resistor dropped 13.7, kirchoff's voltage law would tell us the internal resistor dropped 15-13.7=1.3V.3. R=V/I, Use the current to calculate the internal resistance. 1.3/22.8mA = 56.9ohmsCommentFurther to the above answer, a voltage-source's voltage is not 'dissipated by the internal resistance when on no load'. On no load, there is no current passing through the internal resistance, so no 'voltage dissipation' can takes plac -i.e. the non-load voltage is 15 V.
If Rin = Rout, then the voltage at the output of the device goes down to half of the value that the circuit has without the external resistance. Scroll down to related links and look at "Interconnection of two audio units".
Let the equivalent resistance be R and let there be 3 resistors namely R1,R2 and R3, connected in a parallel way. Now, the relation is: 1/R = 1/R1 + 1/R2 + 1/R3
No. Load resistance is the value of the element actually doing the work of the circuit it is connected to. A speaker connected to an amplifier is the load.
Parallel resistance refers to 2 or more resistors where the input sides are connected together and the output sides are connected together. The formula to calculate it is the inverse of the total resistance of the circuit is equal to the sum of the inverses of the individual resistances. 1/R (total) = 1/R (1) + 1/R (2) + 1/R (3) + …
There is no 'equivalent resistance' for three resistors connected in star.
You need to calculate the equivalent resistance. For instance, if the three resistors are connected in series, simply add all the resistance values up. Then, you calculate the current (in amperes) using Ohm's Law (V=IR); that is, you need to divide the voltage by the resistance.