For incompressible flow the inviscid 1D Euler equations decouple to:
ρt
+ uρx
=
0
px
=0
ut
+
ρ
et
+ uex
=
0
The 3D Euler equations are given by
ρw
ρv
ρu
ρ
ρuw
ρuv
ρu2 + p
ρu
ρv
+ ρuv
+ ρv
2 + p + ρvw
=
0
ρw2 + p
ρvw
ρuw
ρw
(E + p)w
z
(E + p)v
y
(E + p)u
x
E t
where ρ is the density, u =
(u, v, w) are the velocities, E is the total energy per unit volume and p is the
pressure. The total energy is the sum of the internal energy and the kinetic energy.
(
)
1
2
E =ρ
e+
u
2
where e is the internal energy per unit mass. The assumption of incompressiblity
gives
Show that in 3D the inviscid Euler equations with the assumption of incompressible flow decouple to:
The mass conservation equation takes the form:
=
ρe
+ ρ(u2 + v 2 + w2 )/2
∇ · u =
ux
+ vy
+ wz
=
0,
ρt
+ u · ∇ρ
=
0
px
=0
ut
+ u · ∇u
+
ρ
py
vt
+ u · ∇v
+
=0
ρ
pz
wt + u · ∇w
+
=0
ρ
et
+ u · ∇e
=
0
0 =
ρt
+ ∇ · (ρu)
=
ρt
+ ρ∇
· u + u · ∇ρ
=
ρt
+ u · ∇ρ
=
0 .
The momentum equation along the x-axis
can be condensed into
0 =
(ρu)t
+ (ρu2 )x + (ρuv)y
+ (ρuw)z
+ px
=
ρut
+ uρt
+ ρuux
+ u(ρu)x
+ ρvuy
+ u(ρv)y
+ ρwuz
+ u(ρw)z
+ px
=
ρut
+ ρuux
+ ρvuy
+ ρwuz
+ px
+ (ρt
+ (ρv)y
+ (ρu)x
+ (ρw)z
)
=
ρut
+ ρu
· ∇u
+ px
+ (ρt
+ ∇ · (ρu))
⇒ ut
+ u · ∇u
+
px
=0.
ρ
1
A similar argument reveals that the y- and z-axis
momentum equations reduce to their appropriate equations,
giving (in vector form):
∇p
(3)
⇒ ut
+ (u · ∇)u
+
=0.
ρ
Finally, The energy equation can be manipulated in the following way:
0 =
Et
+ ∇ · [(E + p)u]
=
Et
+ ∇ · (Eu) + ∇ · (pu)
=
Et
+ E∇ · u + u · ∇E + p∇
· u + u · ∇p
(
)
(
)
(
)
1
1
1
=
ρ e + u · u + ρt
e + u · u + u · ∇ ρe
+ ρ u · u + u · ∇p
2
2
2
t
(
)
(
)
1
1
=
ρet
+ ρu
· ut
+ ρt
e + u · u + u · ∇(ρe)
+ u · ∇ ρ u · u + u · ∇p
2
2
(
)
(
)
1
1
=
ρet
+ ρu
· ut
+ ρt
e + u · u + ρu
· ∇e
+ eu
· ∇ρ
+
u · u u · ∇ρ
+ ρu
· (u · ∇u)
+ u · ∇p
2
2
)
(
)
(
∇p
1
=
ρet
+ ρu
· ∇e
+ e + u · u (ρt
+ u · ∇ρ)
+ ρu
· ut
+ u · ∇u
+
2
ρ
⇒ et
+ u · ∇e
=
0 .
angular momentum = linear momentum (of object) x perpendicular distance (from origin to the object) where x stands for cross product. angular momentum = mv x r (perpendicular dist.)
The country of manufacture is where it was built and the country of origin is where it was designed, if there really is a difference.
Marconi.
germany
united states
True
The origin of linear equations dates back to ancient civilizations, notably the Babylonians around 2000 BCE, who solved simple linear equations using geometric methods. The formalization of linear equations, however, was significantly advanced by Greek mathematicians like Euclid. The development of algebra in the Islamic Golden Age further refined these concepts, leading to the modern representation of linear equations in the 19th century with the introduction of coordinate systems by René Descartes. Today, linear equations are foundational in various fields, including mathematics, physics, and economics.
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origin and development of hire purchase
The origin was in India and the development is unknown
x2 + y2 = 9
No. The origin must be a solution for any direct variation.
The equation is based on having a centre at the origin. Moving the centre means you have to define where it is in relation to the origin, hence the extra terms involved in that job.
study the origin and development of the universe
origin and develodment of money
The study of the origin and development is called "ontology" or "ontogeny." This field examines the emergence and evolution of beings or entities.
Explain the origin of the defect distribution in a typical software development life cycle.?