Assume the water is initially at 40 F and 14.7 psia.
m = ( 1.0 gal ) ( 1.0 ft^3 /7.4805 gal ) ( 62.43 lbm / ft^3 ) = 8.346 lbm
Q = Delta U = ( m ) ( Cv ) ( T2 - T1 )
Q = ( 8.346 lbm ) ( 1.00 Btu / lbm - Fdeg ) ( 200 F - 40 F ) = 1335 Btu <----------------
8.33 btu if the gallon is US measure, 10 btu if the gallon is british measure.
A btu is the amount of heat required to raise 1 pound of water 1 degree fahrenheit at atmospheric pressure (14.696 psia).
I depends of the starting temperature of the water.
A BTU is the amount of energy required to raise 1 pound of water 1 degree Fahrenheit ... water weighs about 8.34#/gal ... so 8.34 BTU's are required to raise 1 gallon of water 1 degree F. If your starting temperature of the water was 40 degrees F ... there would be 160 degree rise to 200 degrees or ...
1,334 BTU's are required to raise 1 gallon of water from 40 degrees to 200 degrees Fahrenheit
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Since a BTU is defined as the amount of energy required to raise 1 lb of liquid water 1 degree Fahrenheit we could calclate the answer as follows:
19000 lb x (212-166)°F x 1 BTU/lb/°F = 874,000 BTU
This assumes that you only want to raise it to 212°F but not boil it (212 °F is the normal boiling point of water at atmospheric pressure). If you wanted to warm it up AND turn it to vapor, you would have to add 970.4 BTU per pound vaporized. If you vaporized the entire 19000 lb, it would thus take a total of
874,000 + 19000 x 970.4 = 874,000 + 18,437,600 = 19,311,600 BTU
Rounded to the maximum justifiable significant figures it would be 1.93x107 BTU.
The definition of BTU is the amount of energy necessary to raise 1 pound of water by 1 °F (see related link). Taking the density of water (at 40°F) as 8.3451 pounds per gallon, we have 333.804 pounds of water (see other related link). The temperature difference is 212° - 40° = 172°F. So it takes (333.804 BTU) to raise this amount of water by 1°F, so multiply by 172 to get total BTU = 57414 BTU
It takes 8.33 BTU to raise the temperature of water 1 degree F.
You can assume two temperatures, and calculate the amount of energy required to heat the water from one temperature to the other. Then convert that to BTU.
5 Gal of water from 36 TO140F
Approx 8090 BTU
2000
The specific heat of water is 1 BTU per pound per degree Fahrenheit. There are 8.3378 lbs/gallon at 60 degrees, which equals 3251.742 pounds of water. The number of BTUs to raise it 188 degrees is then 611,327.496 BTUs.
Approximately 5,800,000 BTUs per 42-gallon barrel.
A fourty two (42) gallon barrel of oil generates approximately 5,600,000 btus. A cubit foor of nat gas generates 1,200 btus ,there for you would need 4,666.67 cubic feet of gas or 4.6 mcf. Today, an mcf of nat gas costs $2.6 an mcf, a barrel of oil $106. The btu per dollar breakdown looks like this. 5,600,000 btus = 1 barrel of crude oil = $106 5.6m btu / $106 = 52,830 btus per dollar 5,600,000 btus = 4.66 mcf = $12.12 5.6m btus / $12.12 = 462,046 btus per dollar
The question cannot be answered because:the temperature scale being used has not been specified,There is no normal temperature scale in which you can have ice at 32 degrees and steam at 82 degrees without large changes in pressure. If changes in pressure are permitted then there is no simple formula to calculate the amount of heat (btus) required.
6.1030 x 10^6 calories (not food Calories) per liter - this is the mixture of LPG called 'propane' in the proportions used for combustion engines.
The specific heat of water is 1 BTU per pound per degree Fahrenheit. There are 8.3378 lbs/gallon at 60 degrees, which equals 3251.742 pounds of water. The number of BTUs to raise it 188 degrees is then 611,327.496 BTUs.
100 BTU if it's Fahrenheit
You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.
That will completely depend on how much water there is.
25
2250
6,520 Btus
About 114,000 BTU per US gallon.
313 Btu
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
One gallon of kerosene will produce 134,000 BTUs of energy when burned.
None. Changing water from 25 degrees C to 5 degrees C requires heat to be REMOVED, not added!