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The number of aluminium atoms ia 0,44638973.10e23.

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Trever Windler

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1y ago
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11y ago

The gram Atomic Mass of aluminum is 26.9815. 100 grams therefore constitutes 100/26.9815 or about 3.706 gram atoms of aluminum. Each gram atom contains Avogadro's Number of atoms; therefore, 3.706 gram atoms contains 3.706 X 6.022 X 1023 or 2.23 X 1024 atoms, to the justified number of significant digits.

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10y ago

Avogadros constant is 6.022E+23/mol (number of atoms or molecules in 1 mol of any substance). Standard atomic weight of Al is 26.98 g, so we have 26.98 g/mol.

Hence: (26.98 g) / (9 g) = (6.022E+23 / mol) / (x / mol)

x = 2.009E+23

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13y ago

10 grams aluminum (1 mole Al/26.98 grams)(6.022 × 1023/ 1 mole Al)

= 2.2 × 1023 atoms of aluminum

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16y ago

Probably 1,660 538 86.10-14 grams. Excuse the previous answer. Probably 44,803893347889996.10-14 grams.

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7y ago

100 moles of aluminum contain 602,214.10e23 atoms.

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11y ago

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14y ago

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Q: How many atoms of aluminum would be in a 100 grams of aluminum?
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How many aluminum atoms are there in a mass of 16.2 grams?

16. 2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum -------------------------------------------


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