The number of aluminium atoms ia 0,44638973.10e23.
The gram Atomic Mass of aluminum is 26.9815. 100 grams therefore constitutes 100/26.9815 or about 3.706 gram atoms of aluminum. Each gram atom contains Avogadro's Number of atoms; therefore, 3.706 gram atoms contains 3.706 X 6.022 X 1023 or 2.23 X 1024 atoms, to the justified number of significant digits.
Avogadros constant is 6.022E+23/mol (number of atoms or molecules in 1 mol of any substance). Standard atomic weight of Al is 26.98 g, so we have 26.98 g/mol.
Hence: (26.98 g) / (9 g) = (6.022E+23 / mol) / (x / mol)
x = 2.009E+23
10 grams aluminum (1 mole Al/26.98 grams)(6.022 × 1023/ 1 mole Al)
= 2.2 × 1023 atoms of aluminum
Probably 1,660 538 86.10-14 grams. Excuse the previous answer. Probably 44,803893347889996.10-14 grams.
100 moles of aluminum contain 602,214.10e23 atoms.
1
56
16.2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum ------------------------------------------
The formula would be AlCl3, which is aluminum chloride.
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
The ratio in aluminum chloride is 1:3 aluminum to chloride ( AlCl3 or Al2Cl6 )
2
16. 2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum -------------------------------------------
16.2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum ------------------------------------------
The formula would be AlCl3, which is aluminum chloride.
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
None, as pure Aluminium is an element which contains only atoms of Aluminium and nothing else.
2.43 X 1023 atoms aluminum (1 mole Al/6.022 X 1023)(26.98 grams/1 mole Al)(1 pound/454 grams) = 0.024 pounds of aluminum ==================( about 2/5 of an ounce )
17.9 grams
1,99 grams of aluminum is equal to 0,0737 moles.
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
The ratio in aluminum chloride is 1:3 aluminum to chloride ( AlCl3 or Al2Cl6 )
2
Zero.. Aluminum is aluminum and nitrogen is nitrogen.