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What the formula mass for H2S2?
To calculate the formula mass of H₂S₂ (hydrogen disulfide), you add the atomic masses of its constituent elements. Hydrogen (H) has an atomic mass of approximately 1.01 g/mol, and sulfur (S) has an atomic mass of about 32.07 g/mol. Therefore, the formula mass of H₂S₂ is calculated as follows: (2 × 1.01 g/mol) + (2 × 32.07 g/mol) = 2.02 g/mol + 64.14 g/mol = 66.16 g/mol. Thus, the formula mass of H₂S₂ is approximately 66.16 g/mol.
How many moles s are present in 1 g of ammonia?
1 g of ammonia (NH3) is equal to 0,059 mol.
A mixture containing 9 mol of F2 and 4 mol of S is allowed to react. How many moles of F2 remain after 3 mol of S have reacted?
After 3 moles of S have reacted, 3 moles of F2 will also have reacted since the reaction ratio is 1:1 based on the balanced chemical equation. This leaves 6 moles of F2 remaining (9 moles initially - 3 moles reacted).
How many moles of Sc are in 52.3 g of element?
Sc is a s block element. There are 1.16 molesin 52.3 grams.
How many moles of BaSO4 are contained in 142 g of this compound?
To determine the number of moles of BaSO4 in 142 g, first calculate the molar mass of BaSO4 by adding the atomic masses of each element (Ba=137.33 g/mol, S=32.06 g/mol, O=16.00 g/mol) to get 233.39 g/mol. Next, divide the given mass by the molar mass: 142g / 233.39 g/mol ≈ 0.608 moles of BaSO4.
How many 02 molecules are needed to react with 4.82g of S?
The molar mass of S is 32.06 g/mol, so 4.82 g of S is equal to 0.150 mol. In the reaction of S with O2 to form SO2, 1 mol of S reacts with 1 mol of O2. Therefore, 0.150 mol of S would require 0.150 mol of O2, which is equivalent to 0.150 * 6.022 x 10^23, or 9.03 x 10^22 molecules of O2.
Calculate the number of atoms in 0.40 mol of sulfur?
Note that one mole equals 6.022x10^23 of anything in converting. In this case, 1 mole=6.022x10^23 atoms. So we take 0.40 mol of S and convert to calculate how many atoms there are. 0.40 mol S x 6.022x10^23 atoms S/mol S = 2.41x10^23 atoms S
How many grams of sulfuric acid can be made with 75 grams of sulfur?
1 mol of sulfur makes 1 mol of sulfuric acid. The atomic mass of sulfur is 32 g/mol, so 75 g of sulfur is equivalent to 2.34 mol. Since the molar ratio of sulfur to sulfuric acid is 1:1, 2.34 mol of sulfur will make 2.34 mol of sulfuric acid. The molar mass of sulfuric acid is 98 g/mol, so 2.34 mol of sulfuric acid would be equivalent to 229 g.
How many moles in 300.0g S?
To find the number of moles in 300.0g of sulfur (S), divide the mass in grams by the molar mass of sulfur. The molar mass of sulfur is approximately 32.06 g/mol. Therefore, 300.0g of sulfur is equal to 300.0g / 32.06 g/mol = 9.36 moles of sulfur.
How many moles of S are in 22.9g of C6H10S?
To find the number of moles of S in 22.9 g of C6H10S, you need to first calculate the molar mass of C6H10S, which is 126.23 g/mol. Then, divide the given mass by the molar mass to find the number of moles. For S in C6H10S, the molar mass contribution is 32.06 g/mol, so 22.9 g is equivalent to 0.717 moles of S.
What the formula mass for H2S2?
To calculate the formula mass of H₂S₂ (hydrogen disulfide), you add the atomic masses of its constituent elements. Hydrogen (H) has an atomic mass of approximately 1.01 g/mol, and sulfur (S) has an atomic mass of about 32.07 g/mol. Therefore, the formula mass of H₂S₂ is calculated as follows: (2 × 1.01 g/mol) + (2 × 32.07 g/mol) = 2.02 g/mol + 64.14 g/mol = 66.16 g/mol. Thus, the formula mass of H₂S₂ is approximately 66.16 g/mol.
How many mol of Aluminum are required to react completely with 1 mol of CuSO4?
2Al (s) + 3CuSO4(aq) ==> Al2(SO4)3 + 3Cu ... balanced equation1 mol CuSO4 x 2 mol Al/3 mole CuSO4 = 0.67 moles Al required.
How many Units is equivalent to 1 katal?
One katal is equivalent to 1 mole of substrate converted per second in enzymatic reactions. This unit is commonly used to measure catalytic activity, particularly in biochemistry. In terms of other units, 1 katal is equal to 1 mol/s.
How can the theoretical yield of carbon disulfide be calculated when 120 g of methane is reacted with an equal mass of sulfur?
CH4 + 4S --> CS2 + 2H2S 120 g CH4 / 16.04 g/mol = 7.48 mol CH4 120 g S / 32.06 g/mol = 3.74 mol S 1 mol CH4 requires 4x1 mol S 7.48 mol CH4 requires 29.92 mol S S is limiting 3.74 mol S will yield 3.74 / 4 or 0.935 mol CS2 0.935 mol CS2 x 76.1 g/mol = 71.2 g CS2 theoretical yield
How many molecules of H2O are in 0.583 mol of H2O?
There are 3.505 x 10^23 molecules of H2O in 0.583 mol of H2O, because 1 mol of any substance contains 6.022 x 10^23 molecules.
Which reaction shows that the enthalpy of formation of H2S is Hf -20.6 kJ mol?
H2(g) + S(s) H2S + 20.6 kJ
How many moles s are present in 1 g of ammonia?
1 g of ammonia (NH3) is equal to 0,059 mol.
