You need 252 g sulfuric acid.
Mix 120 g sulfuric acid with water to 1000 mL.
Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity.
Sulphuric acid + Zinc ----> Zinc sulphate + Hydrogen H2SO4 + Zn ----> ZnSO4 + H2 (no balancing needed)
according to me, ethane can't be prepared from ethanol. but you can prepare ethene from ethanol by treating ethanol with conc. H2SO4 (95%) In 440 K Temperature with release of water molecule.
H2SO4 is a highly concentrated acid.
You need 49,8 mL H2SO4 6,4M.
how 2.5N H2SO4 prepared from concentrated H2SO4
The answer is 0,526 mL.
h
7n h2so4
Mix 120 g sulfuric acid with water to 1000 mL.
2NH4OH + H2SO4 >> (NH4)2SO4 + 2H2O 8 moles NH4OH (1mol H2SO4/2mol NH4OH)(98.086g H2SO4/1mol H2SO4) = 392.34 grams H2SO4 needed
H2SO4 is needed to first react with HNO3 to give NO2
0.2% of anthrone was dissolved in 100ml of conc H2SO4.
con.H2SO4 is 98%(v/v)ie 980ml/litre.or 980X1.84(specific gravity of H2So4)ie wt/litre is 1803.2Normality= wt per litre/ Eq.wtie 1803.2/49=36.8 NHence con H2So4 is 36.8 NTo prepare 5 N , It has be diluted 7.36 times with water68
112,64 g of NaOH and 138,1 g of H2SO4
heat on hno3 & nh2so3h & make a lot of no2 gas & h2o & h2so4.