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To calculate the heat required to melt 22 g of ice at -18°C, we first need to raise the temperature of the ice to 0°C using the specific heat capacity of ice, which is approximately 2.09 J/g°C. The heat required for this step is ( Q_1 = m \cdot c \cdot \Delta T = 22 , \text{g} \cdot 2.09 , \text{J/g°C} \cdot (0 - (-18)) \approx 22 \cdot 2.09 \cdot 18 \approx 8,190 , \text{J} ). Next, we need to melt the ice at 0°C, which requires the heat of fusion of ice, about 334 J/g; thus, ( Q_2 = 22 , \text{g} \cdot 334 , \text{J/g} \approx 7,348 , \text{J} ). The total heat required is ( Q_{total} = Q_1 + Q_2 \approx 8,190 , \text{J} + 7,348 , \text{J} \approx 15,538 , \text{J} ).

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2w ago

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