You have for an Ideal Gas:
PV = mRT/M
( P2 ) ( V2 )/ (T2 ) ( m2 ) = ( P1 ) ( V1 ) / ( m1 ) ( T1 ) = R/M = Constant
V2 = ( V1 ) ( P1 /P2 ) ( T2/T1 ) ( m2 /m1 )
You have :
( P1 / P2 ) = 1.00
( T2 / T1 ) = 1.00
( m2 / m1 ) = 2.00
V2 = ( V1 ) ( 1.000 ) ( 1.000 ( 2.000 ) = ( 2.000 ) ( V1 ) <-------
Doubling the mass will also double the volume .<----[ Answer ]---
When the mixture is placed in a container half the volume of the original container, the total pressure increases by a factor of two due to Boyle's Law, which states that pressure and volume are inversely proportional as long as temperature is constant. So, the total pressure of the mixture in the smaller container will be double the pressure of the mixture in the original container.
Changing the color of the container will not affect the pressure inside it. Pressure is determined by factors such as temperature, volume, and the number of gas molecules present, not by the container's color.
If you shrink the container containing gas, the volume of the gas decreases because the gas particles are forced into a smaller space. This increase in pressure due to the reduced volume is described by Boyle's Law.
When intrapulmonary volume increases, the intrapulmonary pressure decreases. This creates a pressure gradient that allows air to flow from higher pressure outside the lungs to the lower pressure inside the lungs during inspiration.
If the volume of the container is reduced to one-half of its original size, the pressure will increase proportionally according to Boyle's Law. So if the original pressure was 10 psi, then the new pressure would be 20 psi when the volume is reduced by half.
the volume doubles
When the mixture is placed in a container half the volume of the original container, the total pressure increases by a factor of two due to Boyle's Law, which states that pressure and volume are inversely proportional as long as temperature is constant. So, the total pressure of the mixture in the smaller container will be double the pressure of the mixture in the original container.
In a perfectly flexible and expandable container (pressure is constant) the volume of an ideal gas will double as the absolute temperature doubles. For a non-ideal gas and non-perfect container, your results will vary but will always be somewhat less than double.
In a perfectly flexible and expandable container (pressure is constant) the volume of an ideal gas will double as the absolute temperature doubles. For a non-ideal gas and non-perfect container, your results will vary but will always be somewhat less than double.
If the volume stays the same, the pressure will decrease.
Assuming the volume is kept constant, the pressure will also decrease in this case.
If the volume of a container of air is reduced, the pressure of the air inside the container will increase. This is because the volume and pressure of a gas are inversely proportional according to Boyle's Law. The particles inside the container will collide more frequently with the walls, leading to an increase in pressure.
According to Boyle's Law, the pressure of a gas in a container is inversely proportional to its volume when temperature is constant. This means that as the volume of the container decreases, the pressure of the gas inside will increase, and vice versa.
If you increase the volume of the container, and not the gas itself, then the pressure decreases. If you increase the volume of the gas, and not the container, then the pressure increases.
The pressure of a gas in a container increases when the volume decreases, and decreases when the volume increases, following Boyle's Law. Additionally, the pressure of a gas increases with an increase in temperature, as per Gay-Lussac's Law.
If you double the amount of gas in the same volume you will double the pressure.
Changing the color of the container will not affect the pressure inside it. Pressure is determined by factors such as temperature, volume, and the number of gas molecules present, not by the container's color.