The balanced chemical equation for Barium chloride plus Aluminium sulphate gives Barium sulphate Aluminium chloride is represented as .3BaCl2(aq) + Al2(SO4)3(aq) --> 3BaSO4(ppt) + 2AlCl3(aq).
The ppt formed are white in color.
The reaction equation is: (not the "formula")
Ba2+ + SO42- --> BaSO4
Al2(SO4)3 + 3BaCl2 ----> 2AlCl3 + 3BaS04
BaSO4, also known as barite
Ba2+ + CO32- >> BaSO4
If both of the compounds named in the question are in solution in water, barium sulfate will precipitate. If both are solids when mixed, there will usually be no reaction.
Au(III)SO4,BaSO4
(NH4)2SO4(aq) + BaCl2(aq) → 2NH4Cl(aq) + BaSO4(s). Barium sulfate is the precipitate.
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
The formula unit for the formation of potassium chloride and barium sulfate is one mole. One unit of potassium sulfate and barium chloride are required for the reaction.
Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.
Barium chloride can be precipitated wit a sulfate; barium sulfate is then filtrated.
Since barium chloride is reactive with sulfate ions there would be more precipitate present. The solution with more precipitate present would show it had higher amounts of sulfate ions
since both substance will dissolve, the barium and the sulfate will come together and barium sulfate does not dissolve in water so barium sulfate will be the precipitate.
Ba2+ + CO32- >> BaSO4
The precipitate will be barium sulfate. The reaction is as follows:BaCl2(aq) + Na2SO4(aq) ==> 2NaCl(aq) + Ba(SO4)(s)
If both of the compounds named in the question are in solution in water, barium sulfate will precipitate. If both are solids when mixed, there will usually be no reaction.
Au(III)SO4,BaSO4
BaCl2 + K2SO4 = BaSO4 + 2 KCl .
add water to dissolve the sodium chloride, filter and you can collect the barium sulfate behind the filter paper
By filtration barium sulfate being insoluble in water.