What is the acceleration of a 37kg block when pulled by a force of 170 N?

Answer 1

The acceleration in the block will be 4.59 m/s2

Answer 2

Using the equation F = ma, where F is the force applied (170 N), m is the mass of the block (37 kg), and a is the acceleration, we can solve for a. Rearranging the equation gives a = F/m = 170 N / 37 kg ≈ 4.59 m/s^2. Hence, the acceleration of the 37 kg block when pulled by a force of 170 N is approximately 4.59 m/s^2.