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To find empirical formulas from mass data such as are presented in this question, first convert the masses given to gram atoms by dividing the stated mass for each element by the gram Atomic Mass of the element. For aluminum, 3.704/26.9815 is about 0.137279; for oxygen, 3.295/15.9994 is about 0.205945. Then divide the larger of these numbers of gram atoms by the smaller to produce a quotient of 1.500. The smallest integers that approximate this ratio are 3 and 2. Therefore, the empirical formula is Al2O3.

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Q: What is the empirical formula of a substance that consists of 3.704g aluminum and 3.295g oxygen?

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This the cuprous oxide, CuO.

A molecular formula is the same as or a multiple of the empirical formula. The first step will be to assume exactly 100 grams of the substance, then convert each of these masses to moles,

Because unlike the empirical formula, the molecular formula does not have to be the simplest ratio.If by chance you are given the percent composition of the elements in a substance, you could calculate the empirical formula and then the empirical formula's mass. However, the molecular formula equation is molecular formula= (empirical formula)n, where n is the mass of the molecular formula divided by the mass of the empirical formula. You would, therefore, need to know the mass belonging to the molecular formula, which you are not given.

The empirical mass of NO is 14 + 16 = 30 Divide 138 / 30 ~ = 4.5. The fact that the numbers are not whole number would suggest that the empirical formula is incorrect. However, if we use say NO2 as the empirical formula , then the empirical mass is 14 + 16 + 16 = 46 divide 138 /46 = 3 So NO2 has a formula of N3O6 . This substance does not exist, So it would suggest that the formula is 3NO2 (3/2)N2O4 . I would suggest that the original empirical formula is incorrect. and that the substance is either nitrogen dioxide (NO2) or dinitrogen tetroxide N2O4.

A formula unit is an empirical formula.

Related questions

CH2 is the empirical formula of a substance that consists of 85.60% carbon and 14.4% hydrogen.

Al2S3 is the empirical formula

Formula: AlI3

This the cuprous oxide, CuO.

Al2O3.

Find the mass of the substance and divide it by the mass of the substance defined by the empirical formula. If you get 1, then the empirical formula is also the molecular one.

Al2(SO4)3

Not completely. The empirical formula of a substance can be determined from its percent composition, but a determination of molecular weight is needed to decide which multiple of the empirical formula represents the molecular formula.

Yes it can be

Aluminium oxide is Al2O3, as chemical formula.

An aluminum can is made up of the pure substance, aluminum. This means that it has the chemical formula of Al. The surface of aluminum does oxidize, so it will have the formula Al2O3.

No. The empirical formula of a substance is the formula in which each atomic symbol has the lowest possible subscript that gives the correct ratio between atoms for the compound as a whole. For C6H12, the empirical formula is CH2, but for C6H14, the empirical formula is C3H7.

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