A child has a 25 percent chance of inheriting a disorder if each parent holds a single gene for a recessive disease. This is because the chance of getting a dominant gene that will mask the recessive gene is very high.
It depends on whether the gene is recesstive or domainted. If Its Rr (the trait is domaint) and both parents have it there is a one and four chance the kid won't. Now If the the trait isnt domait theres a one and four chance the kid will get it, and the parents could just be carriers of the trait and not be effected with it. (trait: disease)
If the carrier is the mother and the unaffected person is the father, and the sex-linked disorder is on the X sex chromosome, the probability that they will have a son with the disorder is 50%.
if the trait for that gene is recessive, which it most likely is, than 100%
1/4 (25%) children who's parents both carry the CF gene will themselves inherit Cystic Fibrosis.
There is a 23.56% chance that the child will not suffer if both parents suffer from it.
It will depend on the disorder. Some disorders are not at all hereditary while others are near certainties.
What kind of diseases are the most common genetic diseases? (For example, those in which both parents may be carriers of the disease without knowing it because they don't actually have the disease.)
Parents might decide to have genetic testing to determine if either or both of them carry certain genetic traits that could be passed on to their offspring. Some genetic traits will lead to severe birth defects or problematic diseases that could severely impact the quality of their children's lives. If they are indeed carriers of certain traits, they may choose to avoid having children or choose adoption as an alternative. In this way, they can eliminate their particular genetic line and avoid passing the trait on to the next generation.
IT depends if both parents have it on their genes (X and Y) as Dominant or Recessive, If one of them is dominant, you better expect to get it unless the other parent has a DOminant Counter-Gene
an autosomal recessive disorder, meaning that having an affected offspring requires both unaffected parents to be carriers. Parents who carry the disorder will have a 25% risk of having an affected offspring in subsequent pregnancies.
autosomal dominant is only when one allele is messed upautosomal recessive is when you give the disease to your child 50/50 chance.Not true.... 50/50 when its Autosomal Dominant(see below)Recessive InheritanceBoth parents carry a normal gene (N), and a faulty, recessive, gene (n). The parents, although carriers, are unaffected by the faulty gene. Their offspring are affected, not affected, or carriers. This type of inheritance was first shown by Mendel.Dominant InheritanceOne parent has a single, faulty dominant gene (D), which overpowers its normal counterpart (d), affecting that parent. When the affected parent mates with an unaffected and non-carrier mate (dd), the offspring are either affected or not affected, but they are not carriers.
100%
It is 100% possible that a person who has two parents with the disease will be a carrier of the defective gene.
A carrier means that you have the gene for the disorder, but because the gene is recessive (meaning that it only shows when you have two recessive genes) and you obviously have a dominant gene as well, you won't show the disorder. Someone who actually has the disorder has two recessive genes. D = dominant gene r = recessive gene Dr = carrier, no signs rD = carrier, no signs DD = not a carrier, no signs rr = has the disorder
The sickle cell anaemia is not a deficiency disease. It is a hereditary disease caused by defective gene in both the parents.
Please put the NAME of the disease in your question, so that the question can be answered.
It is an autosomal recessive trait, which means that both of your parents must pass you the defective gene for you to get the disease.
Gaucher disease has a recessive pattern of inheritance, meaning that a person must inherit a copy of the defective gene from both parents in order to have the disease.
It depends on whether your parents are carriers or not. If they are NN (or normal normal) and they have sex with someone who is Nn (or normal gauchers) than using a punnet square the chances of them becoming a carrier are 50 50. If your parents are both carriers ie. Nn Nn then the chances of them becoming a carrier are 50% and them having the disease is 25%. If your parents are nn Nn then the chances of them becoming a carrier is 50% and the chances of them having the disease is 50% so they will either be a carrier or have the disease either way. If your parents are nn NN then there is a 100% chance of them being a carrier. You can figure this out by looking at your family tree and seeing who had the disease before you in your family. This is only very basic Mendelian genetics so i would consult a doctor for a more legitimate answer.
Yes, since the disease is a recessive inherted trait BOTH parents must carry the gene but will not have the disease itself. Approximately 30,000 people in the United States have cystic fibrosis. An additional ten million more-or about one in every 31 Americans-are carriers of the defective CF gene, but do not have the disease. The disease is most common in Caucasians, but it can affect all races.
i think it would be likely, but it would be extremely rare
A female who carries a defective recessive gene on one of her two X chromosomes has a 50% chance of passing the defective gene to her sons who will develop Fabry's disease associated with the defective gene.
If the spouse he or she has the gene needed to pass on cystic fibrosis, then yes it will have children with cystic fibrosis. If the spouse does not have that gene then the child will not have cystic fbrosis but will be a gene carrier of cystic fibrosis.