To calculate the molality of a solution, you need to divide the moles of the solute (in this case, NaCl) by the mass of the solvent (water) in kilograms. First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality by dividing the moles of NaCl by the mass of water in kilograms.
The answer is 0,505.
m = moles/kg = 3.00/1.50 = 2.00 molal
You need to know the molar mass of NaCl. Then 10g/molar mass = moles.
The apparent degree of dissociation of NaCl can be calculated using the formula: i = 1 + (ΔTf)/(Kf * m), where i is the van't Hoff factor, ΔTf is the freezing point depression, Kf is the cryoscopic constant, and m is the molality of the solution. Given the information, assuming Kf for water is 1.86 °C kg/mol and the molality is 0.5 mol/kg, you can calculate the van't Hoff factor to determine the apparent degree of dissociation.
Convert the 200 mol of water to kilograms of water.
To calculate the molality of a solution, you need to know the moles of solute (in this case, NaCl) and the mass of the solvent (water). First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality using the formula molality = moles of solute / mass of solvent in kg.
To calculate the molality of a solution, you need to divide the moles of the solute (in this case, NaCl) by the mass of the solvent (water) in kilograms. First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality by dividing the moles of NaCl by the mass of water in kilograms.
58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085
To calculate the molality of 10 g of NaCl in 2 kg of water, you need to determine the number of moles of NaCl and the mass of the solvent (water) in kilograms. First, calculate the molar mass of NaCl, which is approximately 58.44 g/mol. Then, divide the mass of NaCl (10 g) by its molar mass to find the number of moles, and finally, use the formula for molality: molality = moles of solute / mass of solvent (in kg). In this case, the calculation would be molality = (10 g / 58.44 g/mol) / 2 kg.
To calculate the molality of a solution, you need to know the moles of solute and the mass of the solvent in kilograms. First, calculate the moles of NaCl in 0.2 kg: moles = mass (g) / molar mass. Then, calculate the molality by dividing the moles of solute by the mass of solvent in kg: molality = moles of solute / mass of solvent in kg.
To calculate the molality of NaCl in water, first, determine the number of moles of NaCl by dividing the mass of NaCl (0.2 kg or 200 g) by its molar mass (approximately 58.44 g/mol). Then, divide the number of moles of NaCl by the mass of the solvent (water) in kilograms (3 kg). The formula for molality (m) is m = moles of solute / mass of solvent in kg.
Convert the 200 mol of water to kilograms of water.
Convert the 200 mol of water to kilograms of water.
58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085
convert the .2 kg of NaCl to moles of NaCl.
To find molality, first convert grams of NaCl to moles: 0.630g NaCl / 58.44 g/mol NaCl = 0.0108 mol NaCl. Next, calculate molality using moles of solute and mass of solvent: molality = moles of solute / kg of solvent = 0.0108 mol NaCl / 0.525 kg water = 0.0206 mol/kg.