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Let x = coins that Jimmy has
x + 7 = coins that Tom has
x + (x + 7) = 71
2x + 7 = 71
2x = 64
x = 32 coins for Jimmy
Tom has 39 coins

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Tom has 7 more silver dollars than Jimmy Together they have a total of 71 silver dollars How many silver dollars does Tom have?

39


Tom has 7 more silver dollars than Jimmy together they have a total of 71 silver dollarss how many silver dollars does Tom have?

T - 7 = J T + J = 71, substitute: T + (T - 7) = 71, 2T - 7 = 71, 2T = 78, T = 39, and then J = 32


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