The molar mass of N2 is 28.0134 grams per mole (Atomic Mass of nitrogen times 2).
Multiply that by 7.00 moles to get 196.0938 grams.
Using the 3 significant figures in 7.00, the answer is 196 grams.
See the Related Question link below for more information about how to solve this type of problem!
1 mol of nitrogen contains 12.01 g of nitrogen. From that information you can do a quick proportion... 1 mol = 12.01g x mol = 1.00g you simply divide 1 by 12.01 and you get your answer of 0.083 moles of N
One mole of N2 is 28 grams (Nitrogen has an atomic weight of 14, and one mole of N2 would be 2*14 = 28g)
its just all about guessing.....its the only easy way....ur just like going earlier to hell.......
If you know the atomic weight of the substance, this is equal to the number of grms in a mole of the stuff!
you have 2 molecules. multiply 2 by avagadros number to find the amount of moles of N2. Then multiply by the molecular weight of N2. Hint: Yes, it should be a tiny figure
The answer is 0,00468 moles.
number of moles=molar mass/sample mass
4.52
0,189 g of N2O equal 0,0043 mol.
[ 217(g) / 44.013(g/mol) ] * 2(molN/molN2O) = 9.86 mol NDivide mass (g) by molar mass (g/mol) to get moles of N2O, this should be multiplied by 2 for the stoechiometric factor of atoms N per molecule N2O.
The answer is 1,52 moles.
When using the preferred resonance structure [ N (triple bond) N (single bond) O ] the bond order of N-O in N2O is 1.
1 mole N = 14.0067g N 78.56g N x 1mol N/14.0067g N = 5.609 moles N
There are 0.003659 N2O moles. So there are o.007318 moles of N.
The number of moles is 3,316 (for atomic nitrogen).
0,189 g of N2O equal 0,0043 mol.
[ 217(g) / 44.013(g/mol) ] * 2(molN/molN2O) = 9.86 mol NDivide mass (g) by molar mass (g/mol) to get moles of N2O, this should be multiplied by 2 for the stoechiometric factor of atoms N per molecule N2O.
The answer is 1,52 moles.
Molar mass: 44.013 g/mole 81.0/44.013=1.84 mole N2O Moles of N 1 mole N2O contains 2 atoms N 1.84 mole N2O contain 1.84*2=3.68 mole N atoms
One molecule of N2O N 2 O contains one atom of oxygen.
3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
When using the preferred resonance structure [ N (triple bond) N (single bond) O ] the bond order of N-O in N2O is 1.
The answer is 0,0043 moles of N2.
1 mole N = 14.0067g N 78.56g N x 1mol N/14.0067g N = 5.609 moles N