Power = (voltage)2/Resistance
Resistance = (voltage)2/(Power)
The standard household voltage in North America is 117 V.
Resistance = (117)2/(60) = 228 ohms (rounded)
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Using the formula P = V^2 / R, where P is power (60.0 W) and V is voltage (typically around 120 V in a household circuit), you can calculate the resistance of the light bulb to be approximately 240 ohms.
To calculate the resistance of the 60.0 W light bulb, you need to know the voltage of the household circuit. Using the formula P = V^2 / R (where P is power in watts, V is voltage in volts, and R is resistance in ohms), you can rearrange to solve for resistance: R = V^2 / P. Substitute the given power (60.0 W) and the voltage of your household circuit to find the resistance.
When more light bulbs are added in parallel to a circuit, the total resistance of the circuit decreases. This is because in a parallel circuit, the reciprocal of the total resistance is equal to the sum of the reciprocals of the individual resistances. More paths for current to flow mean less overall resistance in the circuit.
The light bulb was likely the dimmest in the circuit where it had the highest resistance, creating more opposition to the flow of current, resulting in less brightness.
In a series circuit, adding more light bulbs increases the resistance in the circuit. As a result, the total current in the circuit decreases because the voltage remains constant. The current is shared among the components in a series circuit, so adding more bulbs decreases the current that flows through each bulb.
If a bulb with higher resistance is used in a simple circuit, the total resistance in the circuit would increase. According to Ohm's Law (V=IR), with an increase in resistance, the current in the circuit would decrease since the voltage supplied remains constant.