A 60 watt incandescent bulb using 120 Volts draws about one-half amp.
Watts = Volts x Amps (For a resistive load).
By Ohm's Law Volts = Current x Resistance so R = 120 V / .5 A = 240 Ohms.
Doing the same math for a 40 watt bulb you get 360 Ohms.
Power (w) = Volts (v) * Current (I)
I = P/V
100w bulb = 100/230 = 434mA
40w bulb = 40/230 = 174mA
Recall power P = V2/R
For a constant V, P is inversely related to the resistance of the filament.
Hence 40 W bulb would have more resistance than that of 200 W bulb.
The equation that you are looking for is I = E/R. Amps = Voltage/Resistance in ohms.
The light bulb should still have the same limit - 100 watts, because the limit is set practically by how much heat they produce. You need to make sure the wiring in the chandelier is correctly insulated for the higher voltage.
25w
If all the components are rated to 220V, yes. Keep in mind that if the appliance was designed for 110V it may arc if 220 is run through it. If you don't know the device can handle 220V, don't run it at 220V. Chances are it was manufactured cleaply and cannot handle the extra voltage.
The resistance of a piece of wire changes with temperature. In a filament bulb the wire is heated to about 3000 degrees C so a large change in resistance can be expected. A 240 v 105 w halogen bulb has a cold resistance of 35 ohms, but when running its resistance is 549 ohms.
The equation that you are looking for is I = E/R. Amps = Voltage/Resistance in ohms.
Absolutely the more Resistance is put in series the less current Will flow.
In parallel, they both obviously have 220 v across them, so the 100 W bulb is obviously brighter than the 60 W one. The 60 W bulb has more resistance, and in series they both have to pass the same current, so the 60 W has more voltage across it and might be brighter.
A low resistance bulb has a thicker filament.
The light bulb should still have the same limit - 100 watts, because the limit is set practically by how much heat they produce. You need to make sure the wiring in the chandelier is correctly insulated for the higher voltage.
Power is current times voltage, so a current of 0.5 amperes and a voltage of 220v across a bulb will yield a power of 110 watts.
That is e.g. the resistance of a cold bulb before the bulb is lighted and heats up.
3 volt bulb gives the biggest resistance
25w
the filament is made of tunguston which is having high resistance value,Hence it's resistive load
The resistance of a light bulb varies, depending on the type of bulb, the power rating, and the temperature. A typical incandescent 60 watt bulb, for instance has a cold resistance of about 30 ohms, and a hot resistance of about 240 ohms.
The resistance of the filament in a light bulb is(voltage at which the bulb is designed to operate)2/(the rated power/watts of the bulb)