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What is the Comparison between 8086 and 80286 in micro processor?
Wiki User
∙ 13y ago
The 8086/8088 is a 16 bit processor running on a 16 bit (8086) or 8 bit (8088) bus with a 20 bit address. It can address 1 MB of memory. Addressing consists of adding the program's effective address to the (left shifted by 4) value of one of the segment registers. Think of segments as multiple 64kb regions of memory, overlapping at a distance of 16 bytes.
The 80286 is a 16 bit processor running on a 16 bit bus with a 24 bit address. It can address 16mb of memory.
In real mode, it operates the same as an 8086. This is the power on reset state. In protected mode, the segment register changes meaning. Instead of a segment address (left shifted by 4 base address), the segment register is an index into a page descriptor table, which is a table that supports virtual mode. Each element in the page descriptor table also contains information about the protection status of that page, so that page protection can be provided.
Unfortunately, since the meaning of the segment register changed, the 80286 was not object code compatible with programs written for the 8086/8088. This is one of the factors that made the 80286 unpopular.
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∙ 13y ago
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∙ 13y agoTheFreeResource.com has a lot of information about Intel Corp including the answer to this question at http://www.thefreeresource.com/intel-corporation-intel-information-profile-research
Wiki User
∙ 11y ago880186 is very large integration ic which consist of several microprocessor component in single chip therefore it gives twice the performance of 8086.
Wiki User
∙ 14y agoThe 8086/8088 is a 16 bit microprocessor. The 8086 is implemented on a 16 bit data bus, while the 8088 is implemented on an 8 bit data bus.
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∙ 18y agothe
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