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Phenylmagnesium bromide does not have a melting point. It is soluble in diethyl ether and THF and has a flash point of -45 degrees C.

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Phenylmagnesium bromide does not have a melting point. It is soluble in diethyl ether and THF and has a flash point of -45 degrees C.

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Grignard reactions must be carried out in an anhydrous environment in an anhydrous solvent (e.g. anhydrous ether). Why? Grignard reagents behave essentially as a carbanion, and are extremely reactive. Therefore they cannot be carried out while acidic hydrogens, or other positive reactive centers are present (carbonyl compounds such as acetone) in the reaction mixture because there is no way to stop the Grignard from reacting with these other compounds rather than the desired reactant. If phenylmagnesium bromide were prepared, and ANY water was present in the reaction mixture phenylmagnesium bromide would not hesitate to react with water--stealing one of its hydrogens. This hydrogen would therefore replace the attached --MgBr to form benzene.

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The structure of the compound formed is called 1,1-Diphenylethanol. The addition of a weak acid, such as aqueous ammonium chloride is needed for the reaction.

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THIS IS A DIRECT QUOTE FROM YAHOO ANSWERS:

Benzene and magnesium hydroxide and magnesium bromide.

I am betting you are doing a Grignard reaction

Ethyl benzoate + 2 phenylmagnesium bromide --> triphenylmethanol•MgBr salt

if water is present, the grignard reacts with the water first

Phenylmagnesium bromide + H2O --> benzene + MgOHBr

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The MgBr causes the carbon that it's attached to in the phenylmagnesium bromide to become negative and attack the carbonyl carbon of the ethyl benzoate. The carbonly obtains a new bond with a phenyl group and loses its double bond to oxygen. It instead becomes a single bond and oxygen becomes negative (theoretically, the MgBr will attach to the oxygen as an intermediate phase). This attack of the carbon attached to the MgBr will happen a second time creating a carbon attached to 3 phenyl groups (triphenyl) and upon reduction of this compound (using H2 and a catalyst or LiAlH4), -OCH2CH3 gets protonated and leaves as ethanol, and the carbon and oxygen get protonated to CH3OH. I hope this makes sense to you, lol.

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