How much water is in an 18 x 33 foot above ground pool that is 7 ft at its deepest hold?

Answer 1

There are 231 cu.in. in a gallon of water 18'= 216", 33'=396", multiplied together you have 85,539 sq.in. Multiply by the height (in inches) and devide by 231 and you get the gallons in the pool. 3'high=36" 85,539x36= 3,079,296 cu. in. 3,079,296 divided by 231 = 13,330.26 gallons.

Answer 2

Cannot be answered with only these measurements. You need to specify what shape the pool is. Also, for a rectangular pool, the length, width and depth are needed. For a round pool, the diameter and depth are needed.

Answer 3

18-ft x 33-ft x 4-ft = 2,376 cubic feet = 17,773.7 gallons

That's the volume of the pool. We have no way to know

how much water there may be in it.

Answer 4

Go to http://www.havuz.org/pool-calculators.htm

Answer 5

An above ground pool 18x33 - 4ft deep holds about 14k gallons of water. An 18x33 - 4ft above ground pool has about 14k gallons of water.

Answer 6

Formula for Volume: Length X width X depth X 7.48 = gal

Answer 7

Pool gallonage equation is: L x W x Average Depth X 7.5 = ???? gallons of water

Answer 8

26658.72 gallons

Answer 9

About 22,217 gallons of water.