Probability

A coin is flipped eight times What is the probability that the outcome will NOT be eight heads?

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2009-03-13 12:38:08

Probability of not 8 heads = 1- Prob of 8 heads. Prob of 8 heads = 0.5^8 = 0.003906 Prob of not 8 heads= 1- 0.003906 = 0.99604

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Related Questions

That's the same as the total probability (1) minus the probability of seven heads. So: 1 - (1/2)7 = 127/128

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The probability that 2 flipped coins both come up heads is 0.52 or 0.25

The answer depends on how many coins are flipped, and how often.

The sample space is HH, HT, TH, HH. Since the HH combination can occur once out of four times, the probability that if a coin is flipped twice the probability that both will be heads is 1/4 or 0.25.

The probability of flipping Heads on a coin is 1 - a certainty - if the coin is flipped often enough. On a single toss of a fair coin the probability is 1/2.

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The probability that a coin flipped four consecutive times will always land on heads is 1 in 16. Since the events are sequentially unrelated, take the probability of heads in 1 try, 0.5, and raise that to the power of 4... 1 in 24 = 1 in 16

It is neither. If you repeated sets of 8 tosses and compared the number of times you got 6 heads as opposed to other outcomes, it would comprise proper experimental probability.

Your question is a bit difficult to understand. I will rephrase it as follows: What is the probability of getting a head if a coin is flipped once? p = 0.5 What is the probability of getting 2 heads if a coin is flipped twice = The possible events are HT, TH, HH, TT amd all are equally likely. So the probability of HH is 0.25. What is the probability of getting at least on head if the coin is flipped twice. Of the possible events listed above, HT, TH and HH would satisfy the condition of one or more heads, so the probability is 3 x 0.25 = 0.75 or 3/4. Also, since the probability of TT is 0.25, and the probability of all events must sum to 1, then we calculate the probability of one or more heads to be 1-0.25 = 0.75

If both tosses are fair, the probability of that outcome is one in four.

The probability of landing on heads each time a fair coin is flipped, is 1/2.Assuming that the question was supposed to be:"What is the probability of landing on heads twice in a row?"To calculate compound probabilities like this, we first have to work out the probability of landing on heads each time, and then multiply these two probabilities to get a compound probability.1/2 x 1/2 = 1/4So the probability of landing on heads twice in a row = 1/4 (for a fair coin)

The probability of landing on heads at least once is 1 - (1/2)100 = 1 - 7.9*10-31 which is extremely close to 1: that is, the event is virtually a certainty.

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It depends on what variable the probability ratio was for! The random variable could have been the number of heads minus the number of tails, for example.

Experimental Probability: The number of times the outcome occurs compared to the total number of trials. example: number of favorable outcomes over total number of trials. Amelynn is flipping a coin. She finished the task one time, then did it again. Here are her results: heads: three times and tails: seven times. What is the experimental probability of the coin landing on heads? Answer: 3/10 Explanation: Amelynn flipped the coin a total of 10 times, getting heads 3 times. Therefore, the answer is: 3/10.

The side heads is slightly heavier giving it a greater likely hood of landing on tails.