If you are merely drawing from one vertex to all the others, the number of triangles in any n-sided figure is equal to n-2. In this case, a heptagon has seven sides, and thus (7 - 2) = 5 triangles can be drawn.
5
depends on what shape that vertex is in
A hexagon (six-sided polygon) can be divided into 4 triangles by drawing all of the diagonals from one vertex (only three lines can be drawn in this case, since each vertex already connects to two others on the edges of the form). If you instead drew lines from the center to each vertex, you would get 6 triangles.
21
probably, 4. or maybe pi. i believe that the answer is 8.....:)))
By drawing all the diagonals from one vertex, the polygon is divided up into triangles. The sum of the interior angles of the polygon is equal to the sum of the internal angles in the triangles. With n vertices, each vertex is not directly connected to n-3 other vertices, thus n-3 diagonals can be drawn from a vertex which will create n-2 triangles (each with the sum of their interior angles as 180o); so: sum_of_interior_angles = 180 x (number_of_sides - 2)
5 triangles.
3 triangles
Three triangles
4
A regular hexagon can be divided into 6 equilateral triangles by drawing diagonals between opposite vertices, if that helps.
6
You Can Get 6 triangles
Number of sides minus 2 equals the number of triangles within the polygon.
There are 8
depends on what shape that vertex is in
A hexagon (six-sided polygon) can be divided into 4 triangles by drawing all of the diagonals from one vertex (only three lines can be drawn in this case, since each vertex already connects to two others on the edges of the form). If you instead drew lines from the center to each vertex, you would get 6 triangles.
21