Prime Numbers

A three digit prime number where all the digits are divisible by the prime number?

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2011-02-21 00:13:32
2011-02-21 00:13:32

963

3 is the prime

6/3=2

9/3=3

:)

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No, reversing the order of the digits of a two-digit prime number does not always result in a prime number.


73 is the largest two-digit number that is prime and has prime numbers for both of its digits.


73 is the largest 2 digit number that is both prime and has prime numbers for both of its digits.


The largest 3 digit number whose digits are all primes is 777. The largest 3 digit number with different prime digits is 753.


The largest three digit prime number whose digits are all primes is 773.


No, any whole number ending in a digit divisible by 2 is also divisible by 2 and therefore not a prime number.


Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.


304 is NOT a prime number because its last digit is 4, an even digit causing it to be divisible by 2.


It would probably refer to a digit that is a prime number, or a composite number. Note that mathematicians normally talk about prime and composite NUMBERS, not individual digits.


63 has factors other than 1 and itself, so it is not a prime number. For example, 63 is divisible by 3. (You can check this by adding the digits of the number: 6 + 3 = 9. If the sum of the digits is divisible by 3, the number is also divisible by 3.) Therefore, 63 is a composite number.


Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.


A prime number is one that has only two factors: one and itself.You can tell if a number is prime quickly by using the Laws of Divisibility:Numbers that end in 0, 2, 4, 6, and 8 are divisible by 2.If the sum of a number's digit is divisible by 3, the number itself is divisible by 3.If the last two digits of a number are divisible by 4, the number itself is divisible by 4.If a number ends in 0 or 5, it is divisible by 5.If a number is divisible by both 2 and 3, it is divisible by 6.If you double the last digit and subtract it from the rest of the number and the answer is 0 or divisible by 7, it is divisible by 7. For example, 4364: 4 doubled is 8. 436 - 8 = 424. You still cannot readily tell if the number is divisible by 7, so you can do it again: 4 doubled is 8. 42 - 8 = 34. 34 is not divisible by 7 so 436 is not divisible by 7If the last three digits of a number are divisible by 8, the number itself is divisible by 8.If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9.If a number ends with 0, it is divisible by 10.If you add every other digit and then subtract the rest of the digits and the answer is 0 or is divisible by 11, the number itself is divisible by 11. For example: 1364: 1+ 6 = 7 and 7 - 3 - 4 = 0. The number is divisible by 11.If the number is divisible by 3 and 4, it is divisible by 12.There are more divisibility rules that can be used for large numbers.


The smallest prime number in which all of the digits are also prime is 2.The smallest multi-digit prime number in which all of the digits are also prime is 23.



It is a prime number. It is a digit (0,1,2,3,4,5,6,7,8,&9 are digits).


No, this number is divisible by 3 and hence is not a prime number. You can tell that fast by adding the individual digits. If that sum is itself divisible by 3, as this one is, then the number itself is divisible by 3.


four The lowest 5 digits prime number is 10007


There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.There are none.Any number made by using the digits 0 to 9 once is divisible by 9 and so not a prime.




No. Any number ending in the digit 5 is divisible by 5. That means 1985 is not prime.


The last digit is a 5. It is divisible by 5 and is a composite number,


Any number that ends with the digit 5 is divisible by 5.


A prime number is evenly divisible only by itself and one. Any three digit number ending in 0, 2, 4, 6, or 8 is evenly divisible by 2 - so not a prime Any three digit number ending in 5 is divisible by 5, so not a prime number. The only even prime number is 2. The only prime number that ends in 5 is 5.


81 has factors other than 1 and itself, so it is not a prime number. For example, it is divisible by 3. (You can check this by adding the digits of the number: 8 + 1 = 9. If the sum of the digits is divisible by 3, the number is also divisible by 3.) Therefore, 81 is a composite number.



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