A typical statement in the field is the desire to "have a 95 percent probability of meeting time and cost estimates."
The answer depends on the context. From the English alphabet, it is 1/26 = 0.038. In a typical English language document it is approx 0.091. From a set of Scrabbles tiles it is 0.06. From my first name it is 0.
If you have n rings with r numbers in each ring, then the probability of any particular combination is 1/(r^n). r^n denotes r to the power n. So, for a typical lock with three rings, and 10 digits in each ring (0-9), the probability is 1/(10^3) = 1/1000.
In a typical die, there are six sides, so you know that there are six different possible outcomes when you roll it. In this problem, it asks for the probability of either 5 or 6 showing up. To find this simply add 1/6 to 1/6 or multiply 1/6 by 2. Either method will give you the answer of 2/6 which can be simplified to 1/3.
An estimate for the mean of a set of observations is just that - an estimate. Another set of observations will give a different estimates. These estimates for the mean will have a distribution which will have a standard error. If you have two sub-populations, the mean of each sub-population will have a standards error and the se of the difference between the means is a measure of the variability of the estimates of the difference.A typical school work example: the heights of men and of women. There will be a mean height for men, Hm, with a se for men's heights and a mean height for women, Hw, with its own se. The difference in mean heights is Hm - Hw and which will have an estimated se.
Typical: the ordinary
No. In many countries they do not so a "typical" forecast will not.
In typical notation, "p" is the probability of sucess and "q" is the probability of failure. So q = 1 - p. But for your question: p = p.
standard deviation
practice, if really good tours
You would expect there may be other movements, some of which may introduce soloists.
It depends.
building eathren mounds for religious uses
This is a binomial probability distribution with the following criteria: Number of trials = 6, number of successes = 2, probability of success = 1/6 or 0.16667. Because of the probability value not being a typical number, there is not a table to go to look the answer up. The math is tedious. So, we go to a binomial probability calculator and enter in the aforementioned data to obtain the answer of 0.201.
-Risk Categories -Budgeting and Timing -Roles and responsibilities -Probability and impact matrix -Methodology
The probability of having 1 ton of homework is extremely low in a typical educational setting. Homework assignments are usually measured in pages, problems, or hours of work – not weight.
Global estimates are not avilable, but in the United States there are between 1,200 and 1,300 tornadoes in a typical year. They occur most frequently in the spring and early summer.
Models are trained to take great pictures, practice poise, energy/attitude, and the runway walk.