Children's genders are not independent and therefore there is no simple answer.
However, if you do assume that their genders are independent then the probability is 1/3.
The probability will b 0.5. since a coin tossed n times has 2n no. of desired results, among which only half that is n times it can b tail. Hence P = n/2n i.e 0.5.
The probability of at least 1 match is equivalent to 1 minus the probability of there being no matches. The first person's birthday can fall on any day without a match, so the probability of no matches in a group of 1 is 365/365 = 1. The second person's birthday must also fall on a free day, the probability of which is 364/365 The probability of the third person also falling on a free day is 363/365, which we must multiply by the probability of the second person's birthday being free as this must also happen. So for a group of 3 the probability of no clashes is (363*364)/(365*365). Continuing this way, the probability of no matches in a group of 41 is (365*364*363*...326*325)/36541 This can also be written 365!/(324!*36541) Which comes to 0.09685... Therefore the probability of at least one match is 1 - 0.09685 = 0.9032 So the probability of at least one match is roughly 90%
The probability that any given donor is a universal donor is 0.072.We need the probability that the number of universal donors in this group of 20 is not zero or one.Probability of getting zero universal donors: ( 1 - 0.072 )^20 = 0.224367Probability of getting one such donor: 0.348156 (given by the binomial probability density function: probability of one success in 20 trials with p=0.072)Total: 0.224367 + 0.348156 = 0.572523, the probability of zero or one donorsBut we want 1 - 0.572523 = 0.427477, the probability of getting two or more such donors.^ stands for 'to the power of'
(29/78)*(28/77)*(27/76)*(26/75)*(25/74) = .0056252425 two events are dependent if the outcome of one event affects the probability of the other events. The probability that dependent events A and B occur together is P(A and B) = P(A) * P(B given A)
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%
27/64
Data from random samples will not always include the same values. Values are chosen randomly and they may or may not be the same. So means will vary among random samples.
1 out of 3600
Full Question: Among a group of people, 10% are from NYC and 90% are not. All people from NYC are under 18 years old, and 50% of those not from NYC are also under 18 years old. One person is chosen at random, and he or she is under 18. What is the probability that the person chosen is from NYC? Round your answer to two decimal places.
Among the lucky, he is the chosen one.
Among the lucky, he is the chosen one.
Mercy among the Children was created in 2000.
Since you are selecting only among leap years, either the first or the second day of the year would have to be a Saturday, so you have two chances out of seven (a probability of 2/7) that there are 53 saturdays.
There is no proper answer to the question. The children's gender are not independent events: they are affected, among other things by the father's genes and the mother's age. Also, the true probability of a girl is 0.48, not 0.5. However, if you ignore reality, then the answer is (1/2)5 = 1/32.
It is not possible to give a proper answer to the question because the children's are not independent. Among other things they depend on the parents' genetics and their age and there is no information on either of those factors. Also, the probability of a male child is not 0.5 as it is often naively assumed to be. It is, in fat, around 0.52.However, if you suspend reality and assume thatthe children's genders are independent andthe probability of a boy is 1/2then the answer is (1/2)3 = 1/8.
A it is lees likely that differences among them will destroy the test results B the chance of sampling error is unpredictable C the it is almost impossible that differences among them will destroy the test results D the chance OS sampling error is greater E the chance of sampling error is smaller
As per Canon Law, all male Catholics are potential candidates for pope. However, in practicality, only a cardinal is elected. It has been hundreds of years since a non-cardinal has been elected.