an object uniformly accerlerates over a distance of 100 m in 20 seconds. calculate the acceleration.
10m/s
So it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
20 mph/s North
Average acceleration = (change in speed) / (time for the change) = (88 - 44) / (11) = 4 meters per second2
Acceleration has a dimensionality of length/time^2, so if you were measuring the distance in meters and the time in seconds, the acceleration would be m/s^2.
3 / 12 = 0.25 miles/second2.
The car's acceleration can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values gives acceleration = (118 ft/s - 91 ft/s) / 3.20 s = 8.44 ft/s^2. So, the car's acceleration is 8.44 ft/s^2.
So it's acceleration is 4m/s2. So at any point because it says uniformly, it will be accelerating at 4m/s2 each second
The formula for distance traveled with uniformly accelerated motion is d = 0.5 * a * t^2, where d is the distance, a is the acceleration, and t is the time. Plugging in the values: d = 0.5 * 40 * 8^2 = 0.5 * 40 * 64 = 1280 meters. Therefore, the car will travel 1280 meters in 8 seconds.
No
160 m
10.0 seconds
the acceleration of the car is 1.179m/s/s given the formula provided.
Average speed = (250 / 5) = 50 meters per second.Initial speed = 0Final speed = 100 m/sAcceleration = (100 / 5) = 20 m/s2===> Must be a rocket-propelled ball; its acceleration is 2G !
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Converting the initial velocity of 0 km/hr to m/s and final velocity of 60 km/hr to m/s, and plugging in the values, we get the acceleration to be 2 m/s^2.
The acceleration of the body is 3 m/sΒ²
Acceleration= distance / velocity squared
20 mph/s North