surface area of cube = 6a2 = 6 x42 = 84 cm.
Volume of cube= a3= 4 x 4 x 4= 64 cm
Ration of surface area : volume = 84:64 = 21:16
Each surface is 100 sq mm times 6 sides is 600 sq mm. The volume is 10 x 10 x 10 = 1,000 cubic mm. So the ratio is 600 sq mm/ 1,000 cu mm or 6/10.
If a cube has sides of length x cm then area = 6x2 cm2 and volume = x3 cm3
Volume of rectangle is 0
To figure out the surface area of a reactangular prism you have to multiply length x width and then multiply that by how many faces it has, to figure out volume you multiply the length x width x height of the prism and than you will find your answer!!!!!
Volume does not, surface area does.
Surface Area =6 a2= 96 Volume=a3= 64 Ratio of area to volume=84:64 = 21:16
You need to:* Calculate the surface area * Calculate the volume * Divide the surface area by the volume
surface area divided by volume
You measure or calculate the surface area; you measure or calculate the volume and then you divide the first by the second. The surface areas and volumes will, obviously, depend on the shape.
A cube's volume is denoted by side length cubed. This side length is 5 mm, so: V = 5*5*5 V = 5^3 V = 125 cubic mm The surface area of a cube is denoted by 6(s^2) Where s is the side length. SA = 6(5^2) SA = 6(25) SA = 150 sq. mm The ratio of surface area to volume is 150:125 = 6:5
How can you calculate surface density if the volume density is 1.4 g/cm3
You cannot calculate volume of surface area. If you meant 20m3, then the volume would be 20,000 litres.
The volume cannot be 1 centimetre since that is not an appropriate unit for measuring volume.
The surface-area-to-volume ratio may be calculated as follows: -- Find the surface area of the shape. -- Find the volume of the shape. -- Divide the surface area by the volume. The quotient is the surface-area-to-volume ratio.
1. Calculate the surface area 2. Calculate the volume 3. Divide
1) Calculate the area 2) Calculate the volume 3) Divide the area by the volume to get the ratio
Divide the total surface area of the cell by the cell's volume.