0
Nope.
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∙ 12y ago
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Do conversion graphs have to start at 0?
nope!
Do graphs have to start at the number zero?
yes a graph has to start from a point 0.
What do you call Graphs that don't begin at 0?
a line graph
What point do all the graphs of the form y equals ax where a equals 0 have in common?
If y = ax and a = 0, then y=0. No matter what x is, y is still 0. Therefore any graph of y=ax (where a=0) will simply be a line at y=0, which is the x-axis.
When one graphs the square root of 16 as a circle it will cross four lines -4 4 and two imaginary numbers?
No. The 4 points are (4, 0), (0, 4), (-4, 0) and (0, -4).
Do conversion graphs have to start at 0?
nope!
Do graphs have to start at the number zero?
yes a graph has to start from a point 0.
What do you call Graphs that don't begin at 0?
a line graph
What point do all the graphs of the form y equals ax where a equals 0 have in common?
If y = ax and a = 0, then y=0. No matter what x is, y is still 0. Therefore any graph of y=ax (where a=0) will simply be a line at y=0, which is the x-axis.
Why dedicated system memory is 0?
All computers start counting at 0, not 1.
Are the raiders still at the bottom?
No they are not. That's what I like about the start of NFL season...everyone is 0-0.
Why do all conversions start at 0 0?
Anything multiplied by 0 is 0. If your conversion is v = (x*.75), then v = 0 if x = 0.
What words start with 0?
What are all the words that starts with o
When one graphs the square root of 16 as a circle it will cross four lines -4 4 and two imaginary numbers?
No. The 4 points are (4, 0), (0, 4), (-4, 0) and (0, -4).
How are graphs and equations related?
The graph of an equation represents the solution set of the equation, that is all the solutions of the equation are points that lie on the graph and all the points that lie on the graph are solutions of the equation.
Why are graphs of polynomials smooth and continuous?
Smooth function has derivatives of all orders. Polynomials have derivatives of all orders, thus polynomials are smooth functions. For example: f(x)=2x+3 => f'(x)=2 => f''(x)=0 => f'''(x)=0... So all derivatives exist. (Derivative being zero is ok.) Their continuity can be proven using the Weierstrass (epsilon-delta) definition.
How can you solve 2x equals 5y and 3x-2y equals 0 by graphing?
If you were to draw both graphs, then the point that they cross will give you the solutions for both x and y at the same time. To draw the graphs, get them into the form y = mx+c, where m is the gradient and c the y intercept. We have then y = 2/5x +0 & y = 3/2x+0 Therefore the only solution is x = y = 0
