I think so. Even in the case of walk, he can still be picked off by the pitcher.
Yes, if he doesn't he will be called out
No. If a balk occurs with the bases loaded all three runners advance one base, however, the batter does not advance to first base.
yes- if goes out of the baseline before he touches first base, he is out.
Only the batter needs to touch first base to complete the walk.
Yes, The Batter is counted an RBI for every run he bats in regardless of whether he was safe or not.
Good qustion Jeppe. a grand slam is when the bases are loaded ( a runner is on First, Second, and third) and the batter/hitter hits a home run.
If there are fewer than two outs, yes. If there are two outs, both the runner on third and the batter must touch their respective bases for the run to count.
Yes. Since the batter is forced to run to first base the other runners are forced to advance. However, once the batter is put out at first base the other runners may attempt to go back to their original base.
Throw the ball back to the pitcher. A batter can not advance on a dropped third if first base is occupied.
When a batter is walked, they can only go to first base at first. Once they are on first base and the next batter is up to bat, they can steal, or advance on a base hit.
Yes. If the first baseman tags out the batter on his way to first, the three existing runners can return to their original bases; none can be "forced out."
On an interference call that you described, batter/runner is called out and all runners return to the base they were at when the play started. This eliminates any play after the inference which means there is no play at home.
I can think of 12 ways (I answered this question for someone else and onyl thought of ten): Base hit Wild pitch Passed ball Sacrifice fly Squeeze bunt Fielder's choice Ground out by batter Balk by pitcher Batter walked with bases loaded Batter hit by pitch with bases loaded Error on fielder Steal of home What about interference by the catcher on a pitched ball with the bases loaded? Would not the batter be awarded first base, thus forcing the run home from third? Answer We came up with 18: 1. Hit 2. Error 3. Passed Ball 4. Wild Pitch 5. Balk 6. Catcher's Interference 7. Sac Fly 8. Bunt 9. Bases Loaded Walk 10. Bases Loaded HBP 11. Wild pick off throw 12. Wild throw from catcher back to pitcher 13. Steal of home 14. Fielder Interference (Cecile, not Prince) 15. Fan Interference 16. Muffed Infield Fly 17. Fielder's Choice 18. Catcher's Balk
Yes. The batter is awarded first base and all runners would be forced up a base allowing the runner from third to score.
If the batter did not check his swing, (the bat came past home plate), a strike will be called. If he did check his swing, he will advance to first on a hit by pitch, scoring a run. In the former circumstance, the inning will be over if there were previously two strikes on the batter.
If less than 2 outs the batter would be out because 1st base is occupied. If 2 outs then the batter and runners can advance. The catcher or fielder must make the out by retrieving the dropped ball at which point they can tag home, tag the batter or throw the ball to first to make the put out.
no i dont know about in baseball, but in fastpitch softball... the batter would be out
When the ball hits the baserunner it is a dead ball at the runner the ball hit is out. The batter is credited with a single. Since the batter is given a single, any baserunner required to advance will advance, however, no runners ahead of the runner who was out will advance: i.e bases loaded, the runner at 2nd is hit by the ball, the runner at 2nd is out, the runner at 1st goes to 2nd and the batter goes to first. the runner at 3rd does not get to advance, he will stay at 3rd, so the bases will remain loaded runners at 2nd and 3rd, -- the ball hits the guy at 3rd base (while he is in fair territory), runner at 3rd is out, runner at 2nd returns to 2nd, and batter goes to first, you now have runners on 1st and 2nd hope this helps
If he got to first before the out occured it is a single.
Its a live ball if the ball goes back to the backstop he can throw to first or if he blocks the ball he can step on home and get the runner out on third.
The question is confusing, but I'll try to answer it. If a pitcher strikes out a batter but the ball gets past the catcher, both the batter and all base runners may attempt to advance to the next base. The batter must advance to first, thus he put out on a force play at first. All other base runners who must advance on this play (ie, someone on first, or those on first and second) can also be forced out at the base they must advance to. Thus, if the bases are loaded on such a play, all runners must advance, and the runner on third could also be forced out at home. It's because of this fact, that the batter may ONLY advance to first after a dropped third strike when there are no runner force outs possible OR there are two outs. Otherwise, a catcher would "accidentally" drop the ball on a third strike in order to get a double play. Thus, if the bases are loaded and there is a passed ball on a third strike, the batter is out UNLESS there are already two outs. In that latter case, all runners must advance to the next base. A force-out at any base -- including home -- would end the inning with no runs. If the batter and all runners reach base safely (ie, the runner on third comes home), that would be an UNearned run because a runner scored on a passed ball. It would be unearned if the runner on third scored on a passed ball after a third strike or not -- runs are unearned if they result from the play of a fielder instead of the pitcher. One last thing -- if a fielder's play SHOULD have resulted in a third out, but doesn't, then ALL subsequent runs in that inning are unearned. In the batter gets to first on a passed ball on a third strike that should have been the third out, and the next batter gets a home run, then both runs are unearned. If the bizarre scenario I noted above -- dropped third strike on a passed ball with bases loaded with everyone safe (which MUST happen with two outs) -- occurred, and the next batter walked (also with bases loaded) thus getting another run, then that second run would also be unearned.
Ten - First batter reaches steals two bases tagged out at plate. Second batter does the same. Third batter steals two bases and fourth batter steals one. Ten is the answer but alternatively, first batter gets on and steals two bases (2). Next batter reaches first and steals second (3). Third batter reaches first and now with three runners on each base a triple steal could be executed with the 3rd base runner being tagged out (5). Repeat last sentence, (7). Then the fifth batter gets walked, and a triple steal is attempted. The runner from third gets caught in a rundown. The runner from second steals third (8). The runner from first steals second and third (10). Then one of the three runners now between third and home gets tagged out before the lead runner can score.
YES the catcher is SUPPOSED to block the plate as long as he has the ball. if the batter swings and hits the catcher the runner would return to third and the batter awarded first base. If the bases were loaded the catchers interference would force the runner home.