The odd prime digits are 3, 5, and 7. but the final digit of your three-digit Prime number can't be 5. So there are only 18 combinations to check. You can list these numbers and start going through them to see which are prime. The easiest test is divisibility by 3 (sum the digits) and that quickly eliminates 7 of them. You are left with:
337
353
373
533
553x
557
577
733
737x
757
773
Of these, only two are not prime. I marked them with an "x". I used a table of primes to find these and don't know an easier way.
500
180 of them.
It is 120 if the digits cannot be repeated.
There are 34 = 81 numbers.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.
27 three digit numbers from the digits 3, 5, 7 including repetitions.
24
500
There are 60480 numbers.
840
There are 3024 of them.
180 of them.
There are 5*4*3 = 60 such numbers.
1 set
It is 120 if the digits cannot be repeated.
There are 5! = 120 such numbers.