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Can someone help me find the answer for a sample n=36 with a population mean of of 76 and a mean of 79.4 with a standard deviation of 18?
78
A z-score requires the mean and standard deviation (or standard error). There is, therefore, not enough information to answer the question.
Bob scored 300 or 700.
Z-score is the x value minus the mean, all divided by the standard deviation; or z=(x-mu)/sigma. The "x" value needs to be given to answer the question.
z-score of a value=(that value minus the mean)/(standard deviation)
score of 92
To get a z-score one needs a standard deviation and a mean as well as the number.
Information is not sufficient to find mean deviation and standard deviation.
A negative Z-Score corresponds to a negative standard deviation, i.e. an observation that is less than the mean, when the standard deviation is normalized so that the standard deviation is zero when the mean is zero.
A z-score cannot help calculate standard deviation. In fact the very point of z-scores is to remove any contribution from the mean or standard deviation.
.The test has a mean, or average, standard score of 100 and a standard deviation of 16 (subtests have a mean of 50 and a standard deviation of 8). The standard deviation indicates how far above or below the norm the subject's score is.
Can someone help me find the answer for a sample n=36 with a population mean of of 76 and a mean of 79.4 with a standard deviation of 18?
No. The standard deviation is not exactly a value but rather how far a score deviates from the mean.
mean= 100 standard deviation= 15 value or x or n = 110 the formula to find the z-value = (value - mean)/standard deviation so, z = 110-100/15 = .6666666 = .6667
The standard deviation.z-score of a value=(that value minus the mean)/(standard deviation)
78