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Find consecutive negative integers whose sum is 110?
There is no solution.Consecutive negative integers will always add up to a negative number. 110 is positive.
What is the sum 98 find the smaller number The consecutive integers?
No two consecutive integers can add up to 98.No three consecutive integers can add up to 98.But 23, 24, 25, and 26 can.
How should the equation be set up to find the sum of two consecutive odd integers is 24 Find the integers?
n(n+2)(n+4) = 24
The sum of two consecutive positive even integers is 340 what are the integers?
There are no such integers. Proof: choose any positive whole number x two consecutive even integers: (2x) (2x+2) Take the sum (2x)+(2x+2) (2x)+(2x+2)=340 4x+2=340 4x=338 x=338/4=84.5 Since this is not a whole number, there is no whole number that satisfies the conditions. (There are two consecutive odd integers which add up to 340: 169 and 171)
The sum of four consecutive even integers is the same as the least of the integers Find the integers?
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
What is three consecutive even integers whose sum is 36?
10 12 14 are the consecutive even integers which add up to 36
What three consecutive numbers add up to 25?
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
What are three consecutive odd integers that add up to -27?
The integers are -11, -9 and -7.
How many consecutive numbers add up to 1830?
The sum of the first 60 positive integers (1 + 2 + 3 + .... + 59 + 60) is equal to 1830.
What are four consecutive numbers that add up to 36?
This is impossible - no four consecutive integers add to 36.
Three consecutive integers whose sum is 135?
Let's call the three consecutive integers x, x+1, and x+2. The sum of these integers is x + (x+1) + (x+2) = 3x + 3. We know that this sum is equal to 135, so we can set up the equation 3x + 3 = 135. Solving for x gives us x = 44. Therefore, the three consecutive integers are 44, 45, and 46.
The sum of four consecutive odd integers is 200 find these integers?
Let the first integer be x. Since the integers are consecutive odds we know that the integers are x, x+2, x+4,and x+6. Since the sum of all of these is 200 we can set up the equation:4x+12 = 200. Solving we get x=47. Therefore the integers are 47, 49, 51, and 53.
